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2 years ago

HELPPPPPPPP, find x

Mathematics

2 answers:

o-na [289]2 years ago

7 0

Answer: x = 4

Step-by-step explanation:

blondinia [14]2 years ago

4 0

Answer:

x=4

Step-by-step explanation:

3x+5=17 is the equation you need to setup as all square sides are equalivent. Simplify the equation getting 3x=12, Divide all terms by 3 and you get x=4.

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WILL MARK YOU BRAINLIEST HELP ASAP

Marat540 [252]

Answer:

I believe it is c> 34

Step-by-step explanation:

Correct me if i'm wrong

6 0

2 years ago

Read 2 more answers

Suppose three players go on multiple rounds of kart race. In each round, every player has a winning probability of 1/3, independ

zepelin [54]

Answer:

a) 0.3246

b) 0.0043

Step-by-step explanation:

For player 1 ; Probability of winning = P(W) = 1/3

Probability of loosing; P(winning) + P( Loosing) = 1

P(L) = 1 - 1/3 = 2/3

a) To find Find P(N <= 10) = P(2)+P(3)+P(4)+P(5)+P(6)+P(7)+P(8)+P(9)+P(10)

= (1/3)^2 + (1/3)^2 x 2/3 + (1/3)^2 x (2/3)^2 + (1/3)^2x (2/3)^3 + (1/3)^2 x (2/3)^4

X (1/3)^2 x (2/3)^5 + (1/3)^2 x (2/3)^6 + (1/3)^2 x (2/3)^7 + (1/3)^2 x (2/3)^8

= 0.3246

b) Find P(N = 10) = (1/3)^2 x (2/3)^8 = 0.0043

7 0

3 years ago

Waht is the elapsed time for 1:05 pm - 4:40 am

olga2289 [7]

Elapsed time from 105pm to 440am is 15 hours and 35 minutes.

8 0

2 years ago

Read 2 more answers

Please help me with #1 and 2 need for right now thank you

Fiesta28 [93]

For #1 the perimeter if the rectangle would be like 4 vertical and 2 horizontal and the area is 4 x 2= 8

<span>for #2 the first a is 24 the second one for a is 27 the first one for b is 24 and the second one is 35</span>

3 0

3 years ago

Sam entered three functions into a graphing calculator, y1 = x + 2, y2 = x2 + 2, and y3 = 2x. A portion of the table created by

V125BC [204]

For this case we have the following functions:
$y1 = x + 2

y2 = x ^ 2 + 2

y3 = 2 ^ x$

When x = 0 we have:
For y1:
$y1 = 0 + 2

y1 = 2$
For y2:
$y2 = 0 ^ 2 + 2

y2 = 0 + 2

y2 = 2$
Therefore, we have to:
$y1 = y2
$

When x = 5 we have:
For y2:
$y2 = 5 ^ 2 + 2

y2 = 25 + 2

y2 = 27$
For y3:
$y3 = 2 ^ 5

y3 = 32$
Therefore, we have to:
$y2 \ \textless \ y3
$

When x = -1 we have:
For y1:
$y1 = -1 + 2

y1 = 1$
For y2:
$y2 = (-1) ^ 2 + 2

y2 = 1 + 2

y2 = 3
$
For y3:
$y3 = 2 ^ {-1}

y3 = 1/2

y3 = 0.5$
Therefore, we have to:
$y3 \ \textless \ y1 \ \textless \ y2
$

Answer:
When x = 0, y1 = y2
When x = 5, y2 <y3
When x = -1, y3 <y1 <y2

4 0

3 years ago