Question

PLS HELP ASAP! Ty Let g(x)= 2x^2+3x-9 and h(x)=x^2+2x-6 Find (h-g)(2.1)

Answer 1

${\qquad\qquad\huge\underline{{\sf Answer}}}$

Let's solve ~

$\qquad \sf \dashrightarrow \: (h - g)(x)$

$\qquad \sf \dashrightarrow \: h(x) - g(x)$

$\qquad \sf \dashrightarrow \: {x}^{2} + 2x - 6 - (2 {x}^{2} + 3x - 9)$

$\qquad \sf \dashrightarrow \: {x}^{2} + 2x - 6 - 2 {x}^{2} - 3x + 9$

$\qquad \sf \dashrightarrow \: {x}^{2} - 2 {x}^{2} + 2x - 3x - 6 + 9$

$\qquad \sf \dashrightarrow \: - {x}^{2} - x + 3$

For, (h - g)(2.1), put x = 2.1

$\qquad \sf \dashrightarrow \: - {(2.1)}^{2} - (2.1) + 3$

$\qquad \sf \dashrightarrow \: - 4.41 - 2.1 + 3$

$\qquad \sf \dashrightarrow \: - 6.51 + 3$

$\qquad \sf \dashrightarrow \: - 3.51$