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2 years ago

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WHOEVER RESPONDS FIRST WILL GET MARKED BEST. If Kawan paints the visible outside faces of her shed what is the total surface are

a that she paints? 5 ft, 8 ft, 8 ft, 8 ft, and 3 ft.

1 answer:

DIA [1.3K]2 years ago

3 0

the total area will be the sum of the area of the four sides of the shed. In other words it is the curved surface area

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Let T: set of real numbers R Superscript nℝnright arrow→set of real numbers R Superscript mℝm be a linear transformation, and

Klio2033 [76]

Answer:

$\{T(v_1), T(v_2), T(v_3)\}$ is linearly dependent set.

Step-by-step explanation:

Given: $\{v_1,v_2,v_3\}$ is a linearly dependent set in set of real numbers R

To show: the set $\{T(v_1), T(v_2), T(v_3)\}$ is linearly dependent.

Solution:

If $\{v_1,v_2,v_3,...,v_n\}$ is a set of linearly dependent vectors then there exists atleast one $k_i:i=1,2,3,...,n$ such that $k_1v_1+k_2v_2+k_3v_3+...+k_nv_n=0$

Consider $k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0$

A linear transformation T: U→V satisfies the following properties:

1. $T(u_1+u_2)=T(u_1)+T(u_2)$

2. $T(au)=aT(u)$

Here, $u,u_1,u_2$ ∈ U

As T is a linear transformation,

$k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0\\T(k_1v_1)+T(k_2v_2)+T(k_3v_3)=0\\T(k_1v_1+k_2v_2+k_3v_3)=0\\$

As $\{v_1,v_2,v_3\}$ is a linearly dependent set,

$k_1v_1+k_2v_2+k_3v_3=0$ for some $k_i\neq 0:i=1,2,3$

So, for some $k_i\neq 0:i=1,2,3$

$k_1T(v_1)+k_2T(v_2)+k_3T(v_3)=0$

Therefore, set $\{T(v_1), T(v_2), T(v_3)\}$ is linearly dependent.

6 0

3 years ago

Please help me- AND PLEASE EXPLAIN

GuDViN [60]

Answer:

A=35, B=55, and C=25

Step-by-step explanation:

Angle A and the angle next to it are linear pairs, so you can subtract 145 from 180.

if you already know Angle A, and that the other angle is 90 degress, you can add 90+35 and subtract it from 180 to get Angle B

Angle C is paired with the angle across from it (I forgot what the term is called) so it is 25 degrees.

7 0

3 years ago

Find the solution of the given initial value problem. ty' + 6y = t2 − t + 1, y(1) = 1 6 , t > 0

gtnhenbr [62]

Answer:

Step-by-step explanation:

Given is a differential equation as

$ty' + 6y = t^2 - t + 1, y(1) = 1 6 , t > 0$

Divide this by t to get in linear form

$y'+6y/t = t-1+1/t$

This is of the form

y' +p(t) y = Q(t)

where p(t) = 1/t $e^(\int 1/tdt) = t$

So solution would be

$yt = \int t^2-t+1 dt\\= t^3/3-t^2/2+t+C$

siubstitute y(1) = 16

$16 = 16^3/3-128+1+C\\C = -1206$

4 0

3 years ago

Lostsunrise [7]

Answer:

A. x=0

Step-by-step explanation:

x+20+10x=20+9x

cancel equal terms

x+10x+9x

add x to 10x

11x=9x

move variable to left

11x-9x=0

subtract 11x to 9x

2x=0

divide Both sides by 2

x=0

4 0

2 years ago

A granola recipe calls for 2 1/3 cups of almonds. A bag of almonds contains 1/4 cups. How many bags will be needed for the recip

Sholpan [36]

9 I think because 1/4 needs to have 4 of those to be a whole so yeah 9.

8 0

3 years ago