Answer:
y·1.05
Step-by-step explanation:
Solve the following system by Elimination:
{7 x + 3 y = 22 | (equation 1)
{4 y = 20 | (equation 2)
Divide equation 2 by 4:
{7 x + 3 y = 22 | (equation 1)
{0 x+y = 5 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{7 x+0 y = 7 | (equation 1)
{0 x+y = 5 | (equation 2)
Divide equation 1 by 7:
{x+0 y = 1 | (equation 1)
{0 x+y = 5 | (equation 2)
Collect results:
Answer: {x = 1, y = 5
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Solve the following system:
{y - 2 x = 10 | (equation 1)
{4 x - y = -14 | (equation 2)
Swap equation 1 with equation 2:
{4 x - y = -14 | (equation 1)
{-(2 x) + y = 10 | (equation 2)
Add 1/2 × (equation 1) to equation 2:
{4 x - y = -14 | (equation 1)
{0 x+y/2 = 3 | (equation 2)
Multiply equation 2 by 2:
{4 x - y = -14 | (equation 1)
{0 x+y = 6 | (equation 2)
Add equation 2 to equation 1:
{4 x+0 y = -8 | (equation 1)
{0 x+y = 6 | (equation 2)
Divide equation 1 by 4:
{x+0 y = -2 | (equation 1)
{0 x+y = 6 | (equation 2)
Collect results:
Answer: {x = -2, y = 6
Answer:
BZ = 64/23 = 2 18/23
Step-by-step explanation:
The angle bisectors divide the triangle into proportional parts, so we have ...
CB/CY = AB/AY
CB = CY(AB/AY) = 4(8/6) = 16/3 . . . . multiply by CY and evaluate
and ...
BZ/CB = AZ/AC
BZ = AZ(CB/AC) . . . . multiply by CB
But we have ...
AZ = 8 -BZ, so this becomes ...
BZ = (8 -BZ)(16/3)/(10)
BZ(1 +8/15) = 64/15 . . . . add the BZ term on the right to both sides
BZ = (64/15)(15/23) = 64/23 . . . . divide by the coefficient of BZ
BZ = 64/23 = 2 18/23
The formula needed to find the area of a rhombus is (L1*L2)/2
(15.5*13.2)/2
204.6/2
102.3
The area of the farm of the 102.3
