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nataly862011 [7]
2 years ago
12

Please help, thank you guys

Mathematics
1 answer:
DiKsa [7]2 years ago
6 0

Step-by-step explanation:

1) 165⁰

2) 180⁰

Note:FOR initial temperature check the temperature at t=0

I hope it helped you

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Please help me! 7 points!! I don’t understand
SVETLANKA909090 [29]

This is adding two vectors, one magnitude 300 direction east, and one magnitude 100 direction 30 degrees northeast.

For the resulting sum we can use the Law of Cosines or just add up the components.  Let's try it both ways.

Components first.   In the east direction we have

300 + 100 cos 30° = 300 + 100(√3/2) = 386.60 miles per hour

In the north direction we have

0 + 100 sin 30° = 100 (1/2) =  50 miles per hour

So a total speed of

sqrt{386.6^2 + 50^2} = 389.82 miles per hour

Answer: 389.82

--------

OK let's try the Law of Cosines.   We have sides 300 and 100 and included angle 150°.

c^2 = 300^2 + 100^2 - 2 (300)(100) \cos 150^\circ

c=\sqrt{151961.52422} = 389.82 \quad\checkmark

5 0
3 years ago
At the instant that a cake is removed from the oven, the temperature of the cake is 350°F. After 10 minutes, the cake's temperat
BARSIC [14]
Once the cake is removed from the oven, it has been exposed to the room temperature of 70°F. After 10 minutes, the cake's temperature decreased to 200°F, which is 150°F cooler than it initially was (350°F). As for the what is asked, 90°F is 260°F cooler than its original temperature (350°F).

This problem can be expressed in a ratio: 
10mins:150<span>°F = N:260</span><span>°F
where N is how long it will take for</span><span> cake to cool to 90°F

</span>150<span>°FxN=10x260
</span>150N=2600
N=2600/150
N=17.33
N<span>≈20 minutes

Thus, it takes approximately 20 minutes </span><span>for the cake to cool to 90°F</span>
8 0
3 years ago
Please help this is due in tomorrow!!
Nataly_w [17]

Answer:it would be 15cm^2 I think

Step-by-step explanation:

7 0
3 years ago
Which number is prime... 11. 49. 51. 81
Rzqust [24]
The answer to your question is 11
8 0
3 years ago
Three people who work full-time are to work together on a project, but their total time on the project is to be equivalent to th
uranmaximum [27]

Answer:

  1/6

Step-by-step explanation:

Let x represent the proportion of time the third person spends on the project. You want ...

  1/2 + 1/3 + x = 1 . . . . full-time equivalents

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  x = 1/6 . . . . . . . subtract 5/6

The third person should budget 1/6 of their time to the project.

7 0
3 years ago
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