Use substitution.
anywhere you see "a" , than you would plug in b + 2 in for it so....
(b - (b + 2)^4
now take the negative sign and distribute it "+"
so b - b is 0, than 0 - (-2) is -2.
so what is (-2)^4 ????? it would become positive 16
ANSWER
See attachment.
EXPLANATION
The given function is
![y = \sqrt[3]{x + 1} - 2](https://tex.z-dn.net/?f=y%20%3D%20%20%5Csqrt%5B3%5D%7Bx%20%2B%201%7D%20%20-%202)
The parent function is
![y = \sqrt[3]{x}](https://tex.z-dn.net/?f=y%20%3D%20%20%5Csqrt%5B3%5D%7Bx%7D%20)
When we shift the parent graph to the left one unit, and down 2 units, we obtain the graph of the given function.
The graph of this function is shown in the attachment.
Answer:
2nd option
Step-by-step explanation:
You're goal is to isolate b by itself. The only part you need to worry about is the equation, the rest of the word problem is irrelevant.
The whole process of solving this is to do PEMDAS in reverse.
So first add/subtract all the values that does not have a <em>b</em> attach to it to the other side.
then multiply/divide all the values that is not a <em>b</em> to get the b-value by itself
(X+12) + 140 = 180
X + 12 + 140 = 180
X + 152 = 180
X = 180 - 152
X = 28
Im sorry free answer haha...thx!