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Masja [62]
3 years ago
14

Determine if the function is even, odd, or neither.

Mathematics
2 answers:
Gre4nikov [31]3 years ago
6 0

Answer:

6

Step-by-step explanation:

gayaneshka [121]3 years ago
3 0
The answer is going to be 6 so therefore it will be an even number
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Last month Kim trained 3 times as many dogs as cats. If the total number of cats and dogs she trained last month is 28, how many
olga55 [171]
<span>The total number (n) = 28. This includes the number of cats (c) and the number of dogs (d), which is three times the number of cats. Therefore n = c + d and 28 = c + 3c. 28 = 4c. C = 28/4. C = 7. Kim trained 7 cats.</span>
8 0
3 years ago
There are 40 nickels in a roll. If you have 250 rolls of nickels, how many nickels do you have?pls help me
gayaneshka [121]

Answer:

10,000 nickles

Step-by-step explanation:

Since there are 40 nickles in a roll and you have 250, think that you have 250 sets of 40. This means that this question is a multiplication problem.

Multiply 40 x 250. This would give you 10,000.

Don't forget units.

7 0
3 years ago
Read 2 more answers
Use the Euclidean Algorithm to find the greatest common divisor of the polynomials f(x) = x^3 + 3x^2 + 6x + 1 and g(x) = 5x^4 +
fomenos

Answer:

3x+1.

Step-by-step explanation:

First we divide g(x)/f(x) (the process is in the first image):

5x-15 in Z7[x] is 5x-1 and 17x^2+86x+16 is r(x)= 3x^2+2x+2 in Z7[x]. So

g(x)/f(x) = (5x-1)(x^3+3x^2+6x+1)+3x^2+2x+2

Now gcd(g,f) = gcm(f,r).

f(x)/r(x) = 5x(3x^2+2x+2) + 3x+1

Then, gcd(f,r) = gcd(r,3x+1).

r/(3x+1) = (x+5)(3x+1) +4

Then, gcd(r, 3x+1) = gcd(3x+1,4) = 3x+1.

So, gcd(f,g) = 3x+1.

5 0
3 years ago
Find the sum 0.03 + 0.7​
Hunter-Best [27]

Answer: 0.73

Step-by-step explanation:

5 0
3 years ago
Please help 20 points geometry triangle questions​
slava [35]

Answer:

1. yes, SAS

2. yes, ASA

3. yes, SSA

4. yes, SAS

5. no

6. yes, HL and SSA

7. yes, HL and ASA

8. yes, ASA

9. no

10. yes, SSS

11. yes, ASA

12. yes, HL and SSA

13. yes, SAS

14. no

15. no

16. no

17. yes, ASA

18. yes, ASA

19. yes, ASA

5 0
3 years ago
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