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3 years ago

Determine if the function is even, odd, or neither.

Mathematics

2 answers:

Gre4nikov [31]3 years ago

6 0

Answer:

Step-by-step explanation:

gayaneshka [121]3 years ago

3 0

The answer is going to be 6 so therefore it will be an even number

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CAN SOMEONE PLZ HELP ME?? PLZ DO YOU KNOW ABOUT Coordinate Planes??!! AHH

aev [14]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Last summer, Marion was 3 1/2 feet tall. She was 4 inches taller than her brother Elijah. She was 1 1/4 feet shorter than her si

solniwko [45]

Answer:

Answers below

Step-by-step explanation:

Marion: 42 inches

Elijah: 38 inches

Lorie: 57 inches

Convert each to inches and solve.

Hope this helps!

8 0

3 years ago

Perpendicular to the line y=1/2x-8; passes through (7,-6). Write the slope-intercept form of the equation.

Airida [17]

<u>ANSWER: </u>

The slope intercept form of the required line is y = -2x + 20.

<u>SOLUTION: </u>

Given, line equation is $y=\frac{1}{2} x-8$

And, Perpendicular line to the given line passes through (7,-6).

We need to find the slope intercept form of perpendicular line of given line.

We already have the point (7, -6) but we need to find the slope.

Now, we know that, product of slopes of two perpendicular lines equals to -1.

Slope of given line is $\frac{1}{2}$ , by comparing with the general form of slope intercept form.

$\frac{1}{2} \times$ slope of required line = -1

Slope of perpendicular line = -2

Now, line equation of perpendicular line in point slope form is

$y-y_{1}=m\left(x-x_{1}\right)$

y – (-6) = -2(x – 7)

y + 6 = -2x + 14

y = -2x + 20

the above equation is in the form of slope intercept form of a line equation

where slope m = -2 and intercept c = 20

hence, the slope intercept form of the required line is y = -2x + 20.

6 0

3 years ago

Which set of numbers could represent the lengths of the sides of a right triangle?

DiKsa [7]

Answer:

The first set: 8, 15, and 17.

Step-by-step explanation:

By the pythagorean theorem, a triangle is a right triangle if and only if

$\text{longest side}^2 = \text{first shorter side}^2 + \text{second shorter side}^2$ .

In this case,

$\text{longest side}^2 = 17^2 = 289$ .

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 8^2 + 15^2\\ &=64 + 225 = 289 \end{aligned}$ .

In other words, indeed $\text{hypotenuse}^2 = \text{first leg}^2 + \text{second leg}^2$ . Hence, 8, 15, 17 does form a right triangle.

Similarly, check the other pairs. Keep in mind that the square of the longest side should be equal to the sum of the square of the two

Factor out the common factor $2$ to simplify the calculations.

$\text{longest side}^2 = 20^2 = 400$

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 10^2 + 15^2\\ &=100 + 225 = 325 \end{aligned}$ .

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

$\text{longest side}^2 = (2\times 11)^2 = 2^2 \times 121$ .

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= (2 \times 6)^2 + (2 \times 9)^2\\ &=2^2 \times(36 + 81) = 2^2 \times 117 \end{aligned}$ .

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

$\text{longest side}^2 = 11^2 = 121$ .

<h3> $\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 7^2 + 9^2\\ &=49+ 81 = 130 \end{aligned}$ .</h3>

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

6 0

3 years ago

Show your work !!!!!!!!!!!!

sdas [7]

-1/2 < -x/3 < -1/4 = -6/12 < -x/12 < -3/12

two numbers can go in there....-4/12, and -5/12

7 0

3 years ago