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3 years ago

How do I factor this polynomial by grouping? 2x^2 - 13x + 20

2 answers:

6 0

You don' need to grooup
what you do is
factor first term
2=1 times 2
(2x-)(x-)
they are both minus since middle term is negative
now factor other term and get the factors closest together
20=5 times 4

(2x-5)(x-4)
try it out
2x^2-5x-8x+20
2x^2-13x+20

faotred is
(2x-5)(x-4)

if you want to group you do

2 times 20=40
find what 2 numbers multiply to get 40 and add to get -13
numbers are -8 and -5
split it up
2x^2-8x-5x+20
group like factors
(2x^2-8x)+(-5x+20)
undistribute common factors
(2x)(x-4)+(-5)(x-4)
reverse distributive property ab+ac=a(b+c)
(2x-5)(x-4)

katrin2010 [14]3 years ago

6 0

2x^2-13x+20

= (2x-5) (x-4)

I hope that's help !

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3 years ago

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the vertices of PQR are P(-5,1), Q(-4,6), and R(-2,3), graph P"Q"R" after a composition of the transformations in the order they

horsena [70]

SOLUTION

We are told to translate; (x, y) to (x -8, y). This means we have to add - 8 to each value of x in P(-5,1), Q(-4,6), and R(-2,3).

In P(-5,1), x = -5 and y = 1

In Q(-4,6), x = -4 and y = 6 and

In R(-2,3), x = -2 and y = 3

$\begin{gathered} P(-5,\text{ 1) translates to (-5 -8, 1) }\rightarrow P^i(-13,\text{ 1)} \\ Q(-4,\text{ 6) translates to (-4 -8, 6) }\rightarrow Q^i(-12,\text{ 6)} \\ R(-2,\text{ 3) translates to (-2 -8, 3) }\rightarrow R^i(-10,\text{ 3)} \end{gathered}$

For the dilation centered at the origin k =2, simply multiply the value of k, which is 2 into the translations.

$\begin{gathered} At\text{ K = 2, }P^i(-13,\text{ 1) }\rightarrow\text{ }2(-13,\text{ 1) }\rightarrow\text{ }P^{ii}(-26,\text{ 2)} \\ Q^i(-12,\text{ 6) }\rightarrow\text{ }2(-12,\text{ 6) }\rightarrow\text{ Q}^{ii}(-24,\text{ 12)} \\ R^i(-10,\text{ 3) }\rightarrow\text{ }2(-10,\text{ 3) }\rightarrow\text{ R}^{ii}(-20,\text{ 6)} \end{gathered}$

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1 year ago

A survey was conducted on the types of shoes worn by teachers at South Kitsap high school. The Venn diagram below summarizes the

Sophie [7]

Okay, here we have this:

Considering the provided information, we are going to calculate the requested probability, so we obtain the following:

So to calculate the probability of the conjunction of two events we will substitute in the following formula:

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Replacing:

P(wearing brown shoes or tennis shoes U sneakers)=(30+58-8)/100

P(wearing brown shoes or tennis shoes U sneakers)=80/100

P(wearing brown shoes or tennis shoes U sneakers)=0.8

Finally we obtain that the probability that a randomly selected teacher is wearing brown shoes or tennis shoes/sneakers is 0.80.

$undefined$

8 0

1 year ago