All categories

3 years ago

What is 6a^2b^2/2ab^2 in lowest terms

2 answers:

4 0

(-2ab^3)(-3a^2b^5)<span>Simplifying (-2ab3)(-3a2b5) Remove parenthesis around (-2ab3) -2ab3(-3a2b5) Remove parenthesis around (-3a2b5) -2ab3 * -3a2b5 Reorder the terms for easier multiplication: -2 * -3ab3 * a2b5 Multiply -2 * -3 6ab3 * a2b5 Multiply ab3 * a2b5 6a3b<span>8</span></span>

anzhelika [568]3 years ago

4 0

The answer for this question would be: (3a^2b^2 -1) over (b^2)

You might be interested in

Please help i beg i never get these right

Anuta_ua [19.1K]

Answer:

$\sin(105) = \frac{\sqrt 2 + \sqrt 6}{4}$

Step-by-step explanation:

Given

$\sin(105^o)$

Required

Solve

Using sine rule, we have:

$\sin(A + B) = \sin(A)\cos(B) + \sin(B)\cos(A)$

This gives:

$\sin(105^o) = \sin(60 + 45)$

So, we have:

$\sin(60 + 45) = \sin(60)\cos(45) + \sin(45)\cos(60)$

In radical forms, we have:

$\sin(60 + 45) = \frac{\sqrt 3}{2} * \frac{\sqrt 2}{2} + \frac{\sqrt 2}{2} * \frac{1}{2}$

$\sin(60 + 45) = \frac{\sqrt 6}{4} + \frac{\sqrt 2}{4}$

Take LCM

$\sin(60 + 45) = \frac{\sqrt 6 + \sqrt 2}{4}$

Rewrite as:

$\sin(60 + 45) = \frac{\sqrt 2 + \sqrt 6}{4}$

Hence:

$\sin(105) = \frac{\sqrt 2 + \sqrt 6}{4}$

3 0

2 years ago

HELP PLEASE HELP!!!!!

bagirrra123 [75]

(i): A triangle where all three sides are equal and the same.

(ii): A triangle where all three sides are unequal in length.

(iii): A triangle that has two sides of equal length.

(iv): A triangle where all three internal angles are acute(they measure less than 90 degrees.

(v): A triangle where all three internal angles are obtuse(measure above 90 degrees).

(vi): A triangle where one internal angle is a right angle(90 degrees).

Hope this helps

3 0

2 years ago

Read 2 more answers

Type the correct answer in the box. Round your answer to the nearest integer.

umka21 [38]

Answer:

m∠ADC = 132°

Step-by-step explanation:

From the figure attached,

By applying sine rule in ΔABD,

$\frac{\text{sin}(\angle ABD)}{\text{AD}}=\frac{\text{sin}(\angle ADB)}{AB}$

$\frac{\text{sin}(120)}{35}=\frac{\text{sin}(\angle ADB)}{30}$

sin(∠ADB) = $\frac{30\text{sin}(120)}{35}$

= 0.74231

m∠ADB = $\text{sin}^{-1}(0.74231)$

= 47.92°

≈ 48°

m∠ADC + m∠ADB = 180° [Linear pair of angles]

m∠ADC + 48° = 180°

m∠ADC = 180° - 48°

m∠ADC = 132°

4 0

3 years ago

How can 8 ounces be expressed in pounds

vichka [17]

The answer would be .5 pounds

1 ounce is equal to .0625 lbs

so 8 * .0625 = .5

hope this helps :)

brainliest???

4 0

3 years ago

Read 2 more answers

CAN SOMEONE GIVE ME THE STEPS I HAVE THE ANSWERS I JUST NEED THE STEPS

natali 33 [55]

Problem 1:

1) 3/5x-1 x 3/4=9/10

3x/5-1 x 3/4=9/10

2) 3x/5-1 x 3/4=9/10

3x/5-3/4=9/10

3) 3x/5-3/4=9/10

+3/4 +3/4

4) 3x/5=33/20

5) 5 x 3x/5= 5 x (33/20)

6) 3x=33/4

7) 3x=33/4

/3 /3

8) x=11/4

Problem 2:

1) 6/7+2/5x=-4/5

6/7+2x/5=-4/5

2) 6/7+2x/5=-4/5

-6/7 -6/7

3) 2x/5= --58/35

4) 5 x 2x/5= 5 x (--58/35)

5) 2x= --58/7

6) 2x= --58/7

/2 /2

x= --29/7

3 0

3 years ago