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QveST [7]
2 years ago
9

Help!!!! I have rsm tomowrrow. can u also show me how to do it? thanks!

Mathematics
1 answer:
Tpy6a [65]2 years ago
6 0

Check the picture below.

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What is the area of the shape below
Tems11 [23]

8cm, since 6 full squares and 4 halves

hope it helps...!!!

7 0
2 years ago
What is the value of the exponential function f (x)=2 times (1/3)^x when x= -2
frutty [35]

Answer:

18

Step-by-step explanation:

f(x) = 2(1/3)^x

[x = -2]

f(-2) = 2(1/3)⁻²

= 2(9)

= 18

5 0
2 years ago
A nutrition fact label for dried roasted cashews says that there are 161 calories in 28 grams. You eat 9 cashews totaling 12 gra
Vikki [24]

Answer:

21

Step-by-step explanation:

5 0
2 years ago
A petrol kiosk p is 12 km due north of another petrol kiosk q. The bearing of a police station r from p is 135 degree and that f
tiny-mole [99]

Answer:

Distance between P and R is 40.15 km.

Step-by-step explanation:

From the picture attached,

Petrol kiosk P is 12 km due North of another petrol kiosk Q.

Bearing of a police station R is 135° from P and 120° from Q.

m∠QPR = 180° - 135° = 45°

m∠PQR = 120°

m∠PRQ = 180° - (m∠QPR +m∠PQR)

             = 180° - (45° + 120°)

             = 180° - 165°

             = 15°

Now we apply sine rule in ΔPQR to measure the distance between P and R.

\frac{\text{sin}(\angle QPR)}{\text{QR}}= \frac{\text{sin}(\angle PQR)}{\text{PR}}=\frac{\text{sin}\angle PRQ}{\text{PQ}}

\frac{\text{sin}(45)}{\text{QR}}= \frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

\frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

PR = \frac{12\text{sin}(120)}{\text{sin}(15)}

PR = 40.15 km

Therefore, distance between P and R is 40.15 km.

8 0
3 years ago
What is the GCF for 7x2 + 21?
laiz [17]

Answer:

35

Step-by-step explanation:

<u>7x2</u>+21

<u>14+21</u>

35

*The underlined problems is what you do first*

4 0
3 years ago
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