Answer:
9,000
Step-by-step explanation:
I'd suggest you get rid of the fraction first. Mult. every term by 3. You will get
3y^2 + 10y + 3 = 0
From inspection, with coefficient a=3 and coeff. c = 3, the binomial factors could possibly begin with y or 3y: for example, y+1; also, the binom. factors may end in +1. Let's try the possible binomial factor 3y + 1.
Note that 10y separates into 9y+1y.
Then 3y^2 + 10y + 3 = 0 becomes
3y^2 + 9y + 1y + 3 = 0
Let's apply factoring by grouping:
3y^2 + 9y + 1y + 3 = 0
3y*(y + 3) + 1(y + 3) so y+3 is indeed a common factor.
Factoring y+3 out, we get (y+3)(3y + 1), which prove to be the correct set of factors. Multiply these together to ensure that the product is indeed y^2 + (10/3)y + 1.
It says that the value of a box above two boxes is found by adding the expressions in the two boxes. I filled in the boxes. The top box is 13x + 30, or option B.
Answer:
Interval notation: Range = (1,9)
Words notation: Range is between 1 and 9.
Inequality notation: Range = {f(x)| 1 < f(x) < 9}
Step-by-step explanation:
The given function is

We need to find the range of f(x) for the domain -2 < x < 6 .
At x=-2,

At x=6,

So, the range of the function is 1 < f(x) < 9. It can be written as
Interval notation: Range = (1,9)
Words notation: Range is between 1 and 9.
Inequality notation: Range = {f(x)| 1 < f(x) < 9}