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irga5000 [103]
2 years ago
11

I need some help please, what is x?

Mathematics
1 answer:
baherus [9]2 years ago
3 0

Answer:

corner of c and d or d and c

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8,902 to the nearest thousand
7nadin3 [17]

Answer:

9,000

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
How do I solve this quadratic equation by factoring ?
lys-0071 [83]
I'd suggest you get rid of the fraction first.  Mult. every term by 3.  You will get

3y^2 + 10y + 3 = 0

From inspection, with coefficient a=3 and coeff. c = 3, the binomial factors could possibly begin with y or 3y:  for example, y+1; also, the binom. factors may end in +1.    Let's try the possible binomial factor 3y + 1.

Note that 10y separates into 9y+1y.

Then 3y^2 +    10y     +     3  = 0 becomes
         3y^2   + 9y + 1y  +  3  =  0

Let's apply factoring by grouping:

        3y^2 + 9y + 1y + 3 = 0
        3y*(y + 3) + 1(y + 3)    so y+3 is indeed a common factor.

Factoring y+3 out, we get (y+3)(3y + 1), which prove to be the correct set of factors.  Multiply these together to ensure that the product is indeed y^2 + (10/3)y + 1.


3 0
3 years ago
Have no clue what to do
WITCHER [35]
It says that the value of a box above two boxes is found by adding the expressions in the two boxes.  I filled in the boxes.  The top box is 13x + 30, or option B.

3 0
4 years ago
Write the range of f(x) in all three notations if the domain is -2 < x < 6 . f(x)=x+3f(x)=x+3
julia-pushkina [17]

Answer:

Interval notation: Range = (1,9)

Words notation: Range is between 1 and 9.

Inequality notation: Range = {f(x)| 1 < f(x) < 9}

Step-by-step explanation:

The given function is

f(x)=x+3

We need to find the range of f(x) for the domain -2 < x < 6 .

At x=-2,

f(-2)=-2+3=1

At x=6,

f(6)=6+3=9

So, the range of the function is 1 < f(x) < 9. It can be written as

Interval notation: Range = (1,9)

Words notation: Range is between 1 and 9.

Inequality notation: Range = {f(x)| 1 < f(x) < 9}

3 0
3 years ago
Plz show your work.
madreJ [45]
A ....................
8 0
3 years ago
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