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nadezda [96]
3 years ago
15

Simplify 3^4*x*(3/x^2)^-2

Mathematics
1 answer:
astraxan [27]3 years ago
6 0
I think the answer is x^4
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Having a small brain moment, can you please help and show work
ankoles [38]

Answer:

The value if x is 0.9875.

Step-by-step explanation:

First, we have to get rid of brackets by expanding :

0.5(2x +  \frac{3}{4} ) -  \frac{1}{3} (0.1 + x) = 1

0.5(2x) + 0.5( \frac{3}{4} ) -  \frac{1}{3} (0.1) -  \frac{1}{3} (x) = 1

x +  \frac{3}{8}  -  \frac{1}{30}   -   \frac{1}{3} x = 1

Next you have to collect like terms :

x  -  \frac{1}{3} x +  \frac{3}{8}  -  \frac{1}{30}  = 1

\frac{2}{3} x +  \frac{41}{120}  = 1

Lastly, you can solve x :

\frac{2}{3} x = 1 -  \frac{41}{120}

\frac{2}{3} x =  \frac{79}{120}

x =  \frac{79}{120}  \div  \frac{2}{3}

x =  \frac{79}{80}

x = 0.9875

8 0
3 years ago
Angle K and angle L are complementary angles. If angle k = (3x + 3)" and angle k= (10x - 4)". find the
soldier1979 [14.2K]

Answer:

3X+3+10X-4=90

13X-1=90

13X=91

X=91/13=7

<K=10X7-4

70-4

<K=66(SUM OF COMPLEMENTARY ANGLE =90)

<K=24

5 0
3 years ago
What is this word phrase as a math expression?
Arlecino [84]

11 times the sun of a number and 15

11(y+15)

the answer is d

have great day and I hope you make a good grade

3 0
2 years ago
Read 2 more answers
How many moles of oxygen are required to burn 3.0 mole of C10H8 (naphthalene)?
astra-53 [7]

Answer: 36 moles oxygen

Step-by-step explanation:

C10H8 + 12O2 ====》 10CO2 + 4H2O

From the equation of the reaction,

1 mole of napth requires 12 moles of O2

3 moles of napth would require x moles O2

X = (3 * 12) / 1

X = 36 moles of oxygen.

Therefore 3 moles of naphtalene (C10H8) would require 36 moles of oxygen

6 0
3 years ago
What is another way to check my answer for the problem 0.25 x 7
timama [110]
Yhu can divide it......
6 0
3 years ago
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