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kupik [55]
4 years ago
8

How is multiplying and dividing numbers in scientific notation different from adding and subtracting numbers in scientific notat

ion ?
Mathematics
1 answer:
cupoosta [38]4 years ago
6 0

Answer:

multiple and divide are depending on the powers ( sometimes the numbers before the scientific n.)

If the power neg- , it's going down

like this 10^-5 = 1/10^5

If the power pos+ , it's the same idea but different in signs .

Adding and subtracting are depending on numbers ( If the scientific n. is the same number) .

for example:

3x10^5 + 4x10^5 = (3+4)x10^5 = 7x10^5

You might be interested in
A triangle has sides with lengths of 20 meters, 21 meters, and 29 meters. Is it a right triangle?
coldgirl [10]

Answer:

Yes, the sides form a right triangle.

Step-by-step explanation:

<u>Pythagorean Theorem:</u>

a² + b² = c²

↓

20² + 21² = 29²

║a² = 20² = 400

║b² = 21² = 441

║c² = 29² = 841

↓

400 + 441 = 841

║This equation is true.

↓

Yes, the sides form a right triangle.

5 0
3 years ago
Solve the system of equations.
emmainna [20.7K]

x = \frac{ 419 }{ 113 } ~,~y = -\frac{ 208 }{ 113 } ~,~z = \frac{ 21 }{ 113 }

<h2>Explanation:</h2>

We have the following system of three linear equations:

\begin{array}{ cccc }2~ x&+~~4~ y&+~~32~ z&~=~6\\5~ x&+~~8~ y&+~~~~ z&~=~4\\4~ x&+~~5~ y&+~~2~ z&~=~6\end{array}

Let's use elimination method in order to get the solution of this system of equation, so let's solve this step by step.

Step 1: Multiply first equation by -5/2 and add the result to the second equation. So we get:

\begin{array}{ cccc }2~ x&+~~4~ y&+~~32~ z&~=~6\\&-~~~2~ y&-~~~79~ z&~=~-11\\4~ x&+~~5~ y&+~~2~ z&~=~6\end{array}

Step 2: Multiply first equation by −2 and add the result to the third equation. So we get:

\begin{array}{ cccc }2~ x&+~~4~ y&+~~32~ z&~=~6\\&-~~~2~ y&-~~~79~ z&~=~-11\\&-~~~3~ y&-~~~62~ z&~=~-6\end{array}

Step 3: Multiply second equation by −32 and add the result to the third equation. So we get:

\begin{array}{ cccc }2~ x&+~~4~ y&+~~32~ z&~=~6\\&-~~~2~ y&-~~~79~ z&~=~-11\\&&+~~\frac{ 113 }{ 2 }~ z&~=~\frac{ 21 }{ 2 }\end{array}

Step 4: solve for z.

\begin{aligned}       \frac{ 113 }{ 2 } ~ z & = \frac{ 21 }{ 2 } \\      z & = \frac{ 21 }{ 113 }       \end{aligned}

Step 5: solve for y.

\begin{aligned}-2y-79z &= -11\\-2y-79\cdot \frac{ 21 }{ 113 } &= -11\\y &= -\frac{ 208 }{ 113 } \end{aligned}

Step 6: solve for x by substituting y=-\frac{208}{113} and z = \frac{21}{113} into the first equation:

2x+4(-\frac{208}{113})+32(\frac{21}{113})=6 \\ \\ 2x-\frac{832}{113}+\frac{672}{113}=6 \\ \\ 2x=6+\frac{832}{113}-\frac{672}{113} \\ \\ 2x=\frac{838}{113} \\ \\ x=\frac{319}{113}

Finally:

x = \frac{ 419 }{ 113 } ~,~y = -\frac{ 208 }{ 113 } ~,~z = \frac{ 21 }{ 113 }

<h2>Learn more:</h2>

Solving System of Equations: brainly.com/question/13121177

#LearnWithBrainly

7 0
4 years ago
A hypothesis regarding the weight of newborn infants at a community hospital is that the mean is 6.6 pounds. A sample of seven i
shutvik [7]

Answer:

Degree of freedom is 6.

Step-by-step explanation:

A sample of seven infants is randomly selected and their weights at birth are recorded.

Given, Population mean = 6.6 pounds

Sample size = n = 7

Degree of freedom = n - 1

                                = 7 - 1

                                = 6

Degree of freedom is 6.

8 0
4 years ago
1 + 2k = 5k + 7 I got k=2 don't know if it's the right answer ?
DochEvi [55]
You are close, but it is not the correct answer.

1 + 2k = 5k + 7

First, since we are trying to get the variable by itself, we need to move all things to one side. Let's subtract 1 from each side. 
2k = 5k + 7 - 1

Second, we can now subtract (7 - 1) to get 6. Let's add that into our problem and then subtract 5 from each side, still trying to get the variable by itself.
2k - 5k = 6

Third, subtract (2k - 5k) to get -3k. Hint the negative symbol now. If the problem were switched the other way, it would still be a positive. 
-3k = 6

Fourth, we can now divide each side by -3. This results in a fraction and also getting the variable by itself on one side of the problem. Remember the negative sign in front of the fraction since (-3) carried it.
k = - \frac{6}{3}

Fifth, this is our last step. We need to simplify the fraction. Since out fraction is 6/3, which number multiples by 3 to get the answer of 6? The answer is 2, since (3 × 2 = 6). Don't forget the negative!
k = -2

Answer: \fbox {k = -2}
4 0
4 years ago
Kars
8090 [49]

vaka laka vakanlaka vaka laka

6 0
4 years ago
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