Answer: The Break-Even Point will reduce from $4,285.71 to $4,125
Explanation:
To get the Break-Even Point we can divide Fixed Assets by the Contribution margin.
The Contribution Margin is the Selling Price minus the Variable Cost.
For Scenario 1 the Break-Even Point will be,
= 15,000 / ( 6 - 2.50)
= $4,285.71
For Scenario 2 the Break-Even Point is,
= 16,500 / 6.5 -2.5
= $4,125
The Break-Even Point for Scenario 2 means that even though the higher Fixed Costs could have led to a higher Break-Even Point, the higher price contributed more than the fixed costs did and led to an ultimately lower Break-Even Point than the first Scenario.
Answer:
129 bracelets and 59 necklaces.
Explanation:
Kings departments store wants to maximize profit by making a combination of its two products necklaces and bracelets. The King store should use a strategy so that it can generate maximum profit with its available rubies, diamonds and emeralds.
$250a + $500b = Maximum Profit
For rubies : 2a + 5b = 625
For Diamonds : 3a + 7b = 800
For Emeralds: 4a + 3b = 700
Solving the equation we get maximum profit value of $61,750.The King departments stores should make 129 bracelets and 59 necklaces which will bring maximum profit to the store.
Non covalent interactions within the macro molecules determine the three dimensional structures of the macro molecules. Non covalent interactions are also involved in many biological processes in which large molecules bind specifically and transiently to one another. <span />
Answer:
Employees fall under a particular job category. Entrepreneurs create their own profile. Employees have to perform tasks according their respective job profiles. Irrespective of their interest, they are forced to work in an alien environment.
Answer:
The value of the put option is;
e. $9.00
Explanation:
To determine the value of the put option can be expressed as;
C(t)-P(t)=S(t)-K.e^(-rt)
where;
C(t)=value of the call at time t
P(t)=value of the put at time t
S(t)=current price of the stock
K=strike price
r=annual risk free rate
t=duration of call option
In our case;
C(t)=$7.2
P(t)=unknown
S(t)=$50
K=$55
r=6%=6/100=0.06
t=1 year
replacing;
7.2-P=50-55×e^(-0.06×1)
7.2-P=50-(55×0.942)
7.2-P=50-51.797
P=51.797+7.2-50
P=$8.997 rounded off to 2 decimal places=$9.00
