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rjkz [21]
3 years ago
11

One card is randomly selected from a deck of cards. find the odds in favor of drawing a club.

Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
6 0
->Calculate chance for geting any one card in deck, set a proportion
52(total amount of cards) : 100%(total=100%)=1(any one random card) : X%
X=1.9%
->then multiply percentage of any one card with how many clubs are in the deck, there are 13 clubs
X%•13=24.7% chance of getting clubs
Solution is rounded



Sladkaya [172]3 years ago
4 0

Answer:

The odds in favor is 1:3

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Solve for x and y 1/(x+yi) + 2/(x-yi) = 1+i
aliina [53]

Answer:

Step-by-step explanation:

x+i*y≠0 ==> x≠0 and y≠0

x-i*y≠0 ==> x≠0 and y≠0

We must exclude (0,0) as solution.

\dfrac{1}{x+i*y} +\dfrac{2}{x-i*y} =1+i\\\\\dfrac{1*(x-i*y)}{(x+i*y)(x-i*y)} +\dfrac{2*(x+i*y)}{(x-i*y)(x+i*y)} =1+i\\\\\\\dfrac{x-i*y+2x+2i*y}{x^2+y^2} =1+i\\\\3x+i*y=(1+i)(x^2+y^2)\\\\3x+i*y=(x^2+y^2)+i(x^2+y^2+i*(x^2+y^2)\\\\\left\{\begin{array}{ccc}3x&=&x^2+y^2\\y&=&x^2+y^2\\\end {array}\right.\\\\\\\left\{\begin{array}{ccc}y&=&3x\\3x&=&x^2+9x^2\\\end {array}\right.\\\\\\\left\{\begin{array}{ccc}y&=&3x\\x(10x-3)&=&0\\\end {array}\right.\\\\

\left\{\begin{array}{ccc}x&=&0\\y&=&0\\\end {array}\right.\ (to\ exclude) \ or \ \left\{\begin{array}{ccc}x&=&\dfrac{3}{10}\\\\y&=&\dfrac{9}{10}\\\end {array}\right.\\\\Sol=\{(\dfrac{3}{10},\dfrac{9}{10})\}\\

4 0
3 years ago
2/8×7<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B8%7D%20%20%5Ctimes%207" id="TexFormula1" title=" \frac{2}{8} \ti
trasher [3.6K]

Answer:

1 3/4

Step-by-step explanation:

2/8 * 7

2/8 will simplify

Divide the top and bottom by 2

12/8 = 1/4

1/4*7

7/4

We need to change this from an improper fraction to a mixed number

4 goes into 7  once with 3 left over

1 3/4

7 0
3 years ago
From a club of 24 people, in how many ways can a group of four members be selected to attend a conference?
Kamila [148]

Answer:

255,024

Step-by-step explanation:

24 x 23 x 22 x 21

24 options for the first member

23 options for the second member

22 options for the third member

21 options for the last member

6 0
3 years ago
A running club has 90 members.
mezya [45]

Answer:

27, 15, 13

Step-by-step explanation:

5 0
3 years ago
-
TEA [102]

Answer:

0.25. or 1/4

Step-by-step explanation:

The probability that the first coin will be heads is 0.5. The probability that the second coin will be heads is 0.5. So the probability that the first two coins will be heads is 0.5 * 0.5 = 0.25.

Since the third flip can be either heads or tails, this has a probability of 1.0.

So the probability you want is 0.25 * 1.0 = 0.25.    (or if you want a fraction it is 1/4)

3 0
4 years ago
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