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3 years ago

You have two lines. Line A measures 12/16, and line B measures 3/4.

Mathematics

2 answers:

hram777 [196]3 years ago

8 0

Answer:

Step-by-step explanation:

Let's compare the two values of 12/16 and 3/4.

Notice that 12/16 isn't a simplified fraction; both the numerator and denominator are divisible by 4. So divide the top and bottom by 4:

12 / 4 = 3

16 / 4 = 4

We are left with:

12/16 = 3/4

Now, we see that Line A and Line B are equal in length, so the answer is B.

~ an aesthetics lover

jolli1 [7]3 years ago

6 0

B

If you reduce 12 over 16 to its smallest form it changes to 3 over 4

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2 years ago

Divide R300 000 between Leona and Janet in the ratio 3:2.

ella [17]

Answer:

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2 years ago

After their hike, Joe and Mike took a taxi back to the trailhead. The taxi cost $26 plus $0.35 per mile. Which type of function

Sauron [17]

Answer:

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Step-by-step explanation:

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3 years ago

Kevin runs a farm stand that sells apples and raspberries. Each pound of apples sells for $3.50 and each pound of raspberries se

krek1111 [17]

Kevin sold 10 pounds of apples and 20 pounds of raspberries.

Step-by-step explanation:

Given,

Cost per pound of apples = $3.50

Cost per pound of raspberries = $4

Total amount earned = $115

Let,

x represent the pounds of apples sold

y represent the pounds of raspberries sold

According to given statement;

3.50x+4y=115 Eqn 1

y = 2x Eqn 2

Putting value of y from Eqn 2 in Eqn 1

$3.50x+4(2x)=115\\3.50x+8x=115\\11.50x=115$

Dividing both sides by 11.50

$\frac{11.50x}{11.50}=\frac{115}{11.50}\\x=10$

Putting x=10 in Eqn 2

$y=2(10)\\y=20$

Kevin sold 10 pounds of apples and 20 pounds of raspberries.

Keywords: linear equation, substitution method

Learn more about linear equations at:

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3 years ago

Prove that if sin (2 + y) = 3 sin (x - y), then tan x = 2 tany.

nignag [31]

Answer:

The proof is given below.

Step-by-step explanation:

Given: ( the correct question and ans is as follow )

sin (x + y) = 3sin ( x - y)

To Prove

tan x = 2 tan y

Proof:

$\sin (x+y) = 3\sin (x-y)$

Using the identities

$\sin (A+B) = \sin A.\cos B + \cos A.\sin B\\and\\\sin (A-B) = \sin A.\cos B - \cos A.\sin B\\$

we get

$\sin x.\cos y + \cos x.\sin y = 3(\sin x.\cos y - \cos x.\sin y)\\\sin x.\cos y + \cos x.\sin y = 3\sin x.\cos y - 3\cos x.\sin y$

Now we will take sin x . cos y to the left hand side and cos x . sin y to the right hand side,we get

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3 years ago