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LenaWriter [7]
2 years ago
13

A 17- foot ladder is placed against a vertical wall of a building with the bottom of the ladder standing on level ground 11 feet

from the base of the building. How high up the wall does the ladder reach
Mathematics
1 answer:
Hunter-Best [27]2 years ago
7 0

Answer:

y=\sqrt{168} or about 12.96 ft

Step-by-step explanation:

11^2+y^2=17^2

y^2=168

y=\sqrt{168} or about 12.96 ft

You might be interested in
Solve the proportion x/18=7/21​
Crank

Answer:

x=6

Step-by-step explanation:

4 0
2 years ago
Define the double factorial of n, denoted n!!, as follows:n!!={1⋅3⋅5⋅⋅⋅⋅(n−2)⋅n} if n is odd{2⋅4⋅6⋅⋅⋅⋅(n−2)⋅n} if n is evenand (
tekilochka [14]

Answer:

Radius of convergence of power series is \lim_{n \to \infty}\frac{a_{n}}{a_{n+1}}=\frac{1}{108}

Step-by-step explanation:

Given that:

n!! = 1⋅3⋅5⋅⋅⋅⋅(n−2)⋅n        n is odd

n!! = 2⋅4⋅6⋅⋅⋅⋅(n−2)⋅n       n is even

(-1)!! = 0!! = 1

We have to find the radius of convergence of power series:

\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}](8x+6)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}]2^{n}(4x+3)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}](x+\frac{3}{4})^{n}\\

Power series centered at x = a is:

\sum_{n=1}^{\infty}c_{n}(x-a)^{n}

\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}](8x+6)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}]2^{n}(4x+3)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}4^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}](x+\frac{3}{4})^{n}\\

a_{n}=[\frac{8^{n}4^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}]\\\\a_{n+1}=[\frac{8^{n+1}4^{n+1}n!(3(n+1)+3)!(2(n+1))!!}{[(n+1+9)!]^{3}(4(n+1)+3)!!}]\\\\a_{n+1}=[\frac{8^{n+1}4^{n+1}(n+1)!(3n+6)!(2n+2)!!}{[(n+10)!]^{3}(4n+7)!!}]

Applying the ratio test:

\frac{a_{n}}{a_{n+1}}=\frac{[\frac{32^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}]}{[\frac{32^{n+1}(n+1)!(3n+6)!(2n+2)!!}{[(n+10)!]^{3}(4n+7)!!}]}

\frac{a_{n}}{a_{n+1}}=\frac{(n+10)^{3}(4n+7)(4n+5)}{32(n+1)(3n+4)(3n+5)(3n+6)+(2n+2)}

Applying n → ∞

\lim_{n \to \infty}\frac{a_{n}}{a_{n+1}}= \lim_{n \to \infty}\frac{(n+10)^{3}(4n+7)(4n+5)}{32(n+1)(3n+4)(3n+5)(3n+6)+(2n+2)}

The numerator as well denominator of \frac{a_{n}}{a_{n+1}} are polynomials of fifth degree with leading coefficients:

(1^{3})(4)(4)=16\\(32)(1)(3)(3)(3)(2)=1728\\ \lim_{n \to \infty}\frac{a_{n}}{a_{n+1}}=\frac{16}{1728}=\frac{1}{108}

4 0
2 years ago
Please help RIGHT NOW PLEASE HELP NOW
Nikolay [14]

1. it describes what the cost would be for two medium lattes and one small latte all together.

2. it would be the first one which is 2x + y = 7.15

Step-by-step explanation:

5 0
2 years ago
The pH of solution A is 2.4​, while the pH of solution B is 9.4.
pishuonlain [190]

Answer:

The answer to your question is below

Step-by-step explanation:

pH definition

                         pH = - log [H⁺]

a) For pH = 2.4, solution A

                       2.4 = -log[H⁺]

                      [H⁺] = antilog⁻².⁴

                      [H⁺] = 0.00398

  For pH = 9.4, solution B

                       [H⁺] = antilog⁻⁹.⁴

                       [H⁺] = 3.98 x 10⁻¹⁰

b) Divide hydrogen-ion concentration of solution A by hydrogen-ion concentration of solution B.

                             0.00398 / 3.98 x 10⁻¹⁰

                             10000000 times

c) By 7, because 7 is the number of zeros

3 0
3 years ago
what is the answer to this question: Tadeo volunteered at the library 6 times as many hours over the weekend as Dylan. Together,
monitta

Answer:

  • Tadeo: 12 hours
  • Dylan: 2 hours

Step-by-step explanation:

We can let d represent the number of hours that Dylan volunteered. Then Tadeo volunteered for 6d hours, and their total hours were ...

  d +6d = 14

  7d = 14 . . . . . . collect terms

  d = 2 . . . . . . . divide by the coefficient of d

  6d = 6(2) = 12

Tadeo volunteered 12 hours; Dylan volunteered 2 hours.

4 0
2 years ago
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