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LenaWriter [7]
2 years ago
13

A 17- foot ladder is placed against a vertical wall of a building with the bottom of the ladder standing on level ground 11 feet

from the base of the building. How high up the wall does the ladder reach
Mathematics
1 answer:
Hunter-Best [27]2 years ago
7 0

Answer:

y=\sqrt{168} or about 12.96 ft

Step-by-step explanation:

11^2+y^2=17^2

y^2=168

y=\sqrt{168} or about 12.96 ft

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Hi Jakeyriabryant! I hope you’re fine!

I hope I have understood the problem well.

If so, what the exercise raises is the following equality:

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I hope I've been helpful!

Regards!

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