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Llana [10]
2 years ago
7

A camera rental company charges a fixed amount plus a fee based on the number of days for which the camera is rented. The graph

below shows the amount paid for a different number of days to rent the camera: A graph titled Camera Rentals plots the Number of Days on the x axis and the Amount in dollars on the y axis. A straight line joins the ordered pairs 0, 40 and 4, 120. What is the fixed amount charged? $20 $30 $40 $80
Mathematics
1 answer:
Blababa [14]2 years ago
4 0
(0,40)(4,120)
slope = (120 - 40) / (4 - 0) = 80/4 = 20

y = mx + b
slope(m) = 20
(0,40).....this means we have a y int of 40

so ur equation is : y = 20x + 40......this basically means the fee is $ 20 per day....and the fixed amount is $ 40 <===
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I need help with this problem
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Step-by-step explanation:

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2 years ago
5.2.14. For the negative binomial pdf p (k; p, r) = k+r−1 (1 − p)kpr, find the maximum likelihood k estimator for p if r is know
Volgvan

Answer:

\hat p = \frac{r}{\bar x +r}

Step-by-step explanation:

A negative binomial random variable "is the number X of repeated trials to produce r successes in a negative binomial experiment. The probability distribution of a negative binomial random variable is called a negative binomial distribution, this distribution is known as the Pascal distribution".

And the probability mass function is given by:

P(X=x) = (x+r-1 C k)p^r (1-p)^{x}

Where r represent the number successes after the k failures and p is the probability of a success on any given trial.

Solution to the problem

For this case the likehoof function is given by:

L(\theta , x_i) = \prod_{i=1}^n f(\theta ,x_i)

If we replace the mass function we got:

L(p, x_i) = \prod_{i=1}^n (x_i +r-1 C k) p^r (1-p)^{x_i}

When we take the derivate of the likehood function we got:

l(p,x_i) = \sum_{i=1}^n [log (x_i +r-1 C k) + r log(p) + x_i log(1-p)]

And in order to estimate the likehood estimator for p we need to take the derivate from the last expression and we got:

\frac{dl(p,x_i)}{dp} = \sum_{i=1}^n \frac{r}{p} -\frac{x_i}{1-p}

And we can separete the sum and we got:

\frac{dl(p,x_i)}{dp} = \sum_{i=1}^n \frac{r}{p} -\sum_{i=1}^n \frac{x_i}{1-p}

Now we need to find the critical point setting equal to zero this derivate and we got:

\frac{dl(p,x_i)}{dp} = \sum_{i=1}^n \frac{r}{p} -\sum_{i=1}^n \frac{x_i}{1-p}=0

\sum_{i=1}^n \frac{r}{p} =\sum_{i=1}^n \frac{x_i}{1-p}

For the left and right part of the expression we just have this using the properties for a sum and taking in count that p is a fixed value:

\frac{nr}{p}= \frac{\sum_{i=1}^n x_i}{1-p}

Now we need to solve the value of \hat p from the last equation like this:

nr(1-p) = p \sum_{i=1}^n x_i

nr -nrp =p \sum_{i=1}^n x_i

p \sum_{i=1}^n x_i +nrp = nr

p[\sum_{i=1}^n x_i +nr]= nr

And if we solve for \hat p we got:

\hat p = \frac{nr}{\sum_{i=1}^n x_i +nr}

And if we divide numerator and denominator by n we got:

\hat p = \frac{r}{\bar x +r}

Since \bar x = \frac{\sum_{i=1}^n x_i}{n}

4 0
3 years ago
Tom, Mary and Bill are aged 10,12 and 15 years respectively. They share 259 euros in the same ratio as their ages. Find how much
tigry1 [53]

Answer:

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Step-by-step explanation:

sum their ages , 10 + 12 + 15 = 37

divide the amount by this sum to find the value of one part of the ratio.

259 ÷ 37 = 7 ← value of 1 part of the ratio , then

10 parts = 10 × 7 = 70 euros ← Tom's share

12 parts = 12 × 7 = 84 euros ← Mary's share

15 parts = 15 × 7 = 105 euros ← Bill's share

7 0
2 years ago
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Oksi-84 [34.3K]
Rents his place for $125 per day and his goal has to be in 5 days. Lets use 125 times 5 days then each chime sold is $12 and we need the number of chimes sold so we use "x" as our variable. Equation 125(5) + 12x = 3500. Hope this helps.
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