Answer please! 2/x -4/y ———

Which number is equal to 10 to the power of neg 3

Shkiper50 [21]

Answer:

0.001

Step-by-step explanation:

4 0

3 years ago

How many unique triangles can be drawn with given side lengths of 8 inches, 10.3 inches, and 13 inches?

REY [17]

Answer: 1

Step-by-step explanation: There can only be one triangle like that!

4 0

2 years ago

Read 2 more answers

Can someone help me out with this please? I suck at fractions

xxMikexx [17]

164 inches x $\frac{1 foot}{12 inches}$ = $\frac{41}{3}$ ft

147 inches x $\frac{1 foot}{12 inches}$ = $\frac{49}{4}$ ft

2 $\frac{1}{4}$ ft = $\frac{9}{4}$

Perimeter = 2L + 2w - 1doorway

= 2 $(\frac{41}{3})$ + 2( $(\frac{49}{4})$ - $\frac{9}{4}$

= $\frac{82}{3}$ + $\frac{98}{4}$ - $\frac{9}{4}$

= $\frac{82}{3}$ + $\frac{89}{4}$

= $(\frac{4}{4} )$ $\frac{82}{3}$ + $(\frac{3}{3} )$ $\frac{89}{4}$

= $\frac{328}{12}$ + $\frac{267}{12}$

= $\frac{595}{12}$

= 49 $\frac{7}{12}$ ft

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b) 49 $\frac{7}{12}$ ft ÷ 8ft = 6.2

7 boards need to be purchased

5 0

2 years ago

The sum of a number and 6 is 23 write an equation to represent this situation

m_a_m_a [10]

The sum is the answer to an addition problem. Since we know the sum involves addition, we write an addition equation between the variable and the number given to us.
6 + n (number that was not given to use) = 23

5 0

3 years ago

There is 5/8 of an hour before the end of soccer practice. It takes 1/6 of an hour for the team to complete 1 full scoring drill

Makovka662 [10]

Answer:

Three full scoring drill can be completed in $\frac{5}{8}$ hrs with $\frac{1}{8}$ hrs still remaining in end of practice session.

Solution:

Given that

Time remaining before end of soccer practice in hours = $\frac{5}{8}$

Time required for 1 full scoring drill = $\frac{1}{6}$

Need to identify how many drills can be complete before practice is over.

For sake of simplicity lets make denominators of both the numbers same.

$\frac{5}{8}=\frac{5}{8} \times \frac{3}{3}=\frac{15}{24}$

$\frac{1}{6}=\frac{1}{6} \times \frac{4}{4}=\frac{4}{24}$

$\frac{4}{24}$ is time for 1 drill

Lets say $\frac{4}{24} = d$

Time remaining = $\frac{15}{24} = \frac{4 + 4 + 4+ 3}{24} = \frac{4}{24} + \frac{4}{24} + \frac{4}{24} + \frac{3}{24} = d + d +d + \frac{3}{24}$

$\frac{15}{24} = 3d + \frac{3}{24}$

3d means three drills will be completed. Fourth drill will not complete because $\frac{3}{24}$ is not sufficient to complete a drill.

Hence mathematical representation of given situation is

$\frac{5}{8} = 3d + \frac{1}{8}$

Where d is the time required to complete one drill equal to $\frac{1}{6}$ of hour.

So three full scoring drill can be completed in $\frac{5}{8}$ hrs with $\frac{1}{8}$ hrs still remaining in end of practice session.

8 0

2 years ago

Answer please! 2/x -4/y ———— -5/y + 3/x