Write the slope-intercept form of the equation of the line that is parallel to AB and passes through Point X. Show all

Mathematics

1 answer:

DanielleElmas [232]2 years ago

7 0

find y=mx+b for line parallel to AB.

The line that is parallel will have the same slope as line AB:

the slope of line AB is

m=(8-3)/(-10-2)

=5/-12

=-5/12

Since the line going through X is parallel the vertical distance of the new line to AB is the same for all values of the domain(x-axis).

at x=-5 the point X has the y value of 10 which is 4 more than the y value for AB based on the graph.

To find the intercept b of the line going through X that is parallel to AB we just add 4 to the intercept of AB, which is 4 so

4+4=8

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Write the point-slope form of the line that passes through (-8, 2) and is perpendicular to a line with a slope of -8

Schach [20]

Answer:

y - 2 = (1/8)(x + 8)

Step-by-step explanation:

The slope of the given line is -8. That means the slope of any line perpendicular to the given line will be the negative reciprocal of -8, which would be (1/8).

Then the desired equation is

y - 2 = (1/8)(x + 8)

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3 years ago

Follow the steps to solve for the variable in this two-step equation:

lesya692 [45]

The solution of the equation is x = 2

Step-by-step explanation:

The original equation is

$5x-10 = 0$

We solve it using the following steps:

1) We apply the addition property of equality: by adding the same factor on both sides of the equation, the equation does not change.

In this case, we add +10 on both sides, and we get:

$5x-10+10=0+10\\5x=10$

2) We apply the division property of equality: by dividing both sides of the equation by the same number (different from zero), the equation does not change.

In this case, we divide both sides of the equation by 5, and we get:

$\frac{5x}{5}=\frac{10}{5}\\x=2$