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lubasha [3.4K]
2 years ago
13

A bouncy ball is dropped such that the height of its first bounce is 5.5 feet and each successive bounce is 73% of the previous

bounce's height. What would be the height of the 7th bounce of the ball? Round to the nearest tenth (if necessary).
Mathematics
1 answer:
sineoko [7]2 years ago
3 0
The answer is one because the exact answer is 0.9788 and then they’re asking you to round
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Given right triangle JKL, what is the value of cos(L)?
Daniel [21]

First option is correct.

Since we have given that

JKL is a right triangle.

Length of JK = 12

Length of KL = 5

By Pythagoras theorem, we get that

JL^{2}=JK^{2}+ KL^{2}\\JL^{2}=12^{2}+ 5^{2} \\JL^{2}=144+25= 169\\JL=13

So, cos (L) would be

cos(L)=base/hypotenuse

cos(L)=5/13

Hence, First option is correct.

learn more about Pythagoras theorem and cosine ratios here:

brainly.com/question/9027282

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Brrunno [24]

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2 years ago
A ballplayer catches a ball 3.4s after throwing it vertically upward. with what speed did he throw it, and what height did it re
Daniel [21]

From the equation of motion, we know,

s=ut+\frac{1}{2}at^{2}

Where s= displacement

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a= gravitational force

t= time

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A = -9.8m/s^{2} since the ball is thrown upwards.

Plug the known values into the equation.

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u= 16.67 m/ sec ....... equation (1)

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Time take to reach the top = \frac{3.4}{2} = 1.7 sec

v^{2}=u^{2}+2as

=> 0=(16.67)^{2}+2(-9.81)(s)

Solving for s we get

s= 14.16 m


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3 years ago
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5 0
3 years ago
Fill in the blanks to make each equation true.
n200080 [17]

Answer: all true

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6 0
3 years ago
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