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⇒ (x - 3)² = 5
⇒ x² - 6x + 9 = 5
⇒ x² - 6x + 4 = 0
⇒ x = -(-6) ± √36 - 4(1)(4) / 2
⇒ x = 6 ± √20 / 2 = 6 ± 2√5 / 2
⇒ x = 3 ± √5
∴ The solutions are x = 3 + √5 and x = 3 - √5.
Answer:
20165
Step-by-step explanation:
Given:
Length/height (h) of cylindrical test tube = 152 mm
Radius of cylindrical test tube = 6.5 mm
Volume = 
Required:
Volume of cylinder to nearest whole number
Solution:
The volume is given as 
Take π as 3.14 and plug the values of r and h into the volume formula.


Volume of the test tube = 20165 mm³ (nearest whole number)
Answer:
She is incorrect
Step-by-step explanation:
Pythagorean theorem:
16^2+8^2
256+64=320
320 is 17.89
8^2+8^2
64+64=128
√128 is 11.31
Ada is incorrect. The length of diagonal SQ is bigger than the length of diagonal OM. But it is not two times bigger.
Answer:

Step-by-step explanation:
Use cosine:


We have:

Substitute:

<em>cross multiply</em>
<em>divide both sides by 9063</em>
