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2 years ago

A FIGURE HAS AN AREA OF 50 UNITS.WHAT WILL THE NEW AREA BE AFTER A DILATION WITH SCALE FACTOR OF 3

Mathematics

1 answer:

xenn [34]2 years ago

6 0

Answer:

150 units

Step-by-step explanation:

50 x 3 = 150

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Could someone pls explain logarithms to me ,l don't understand it at all.l think l am going to fail this subject.

Bad White [126]

Answer:

In mathematics, the logarithm is the inverse function to exponentiation. That means the logarithm of a given number x is the exponent to which another fixed number, the base b, must be raised, to produce that number x.

Step-by-step explanation:

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3 years ago

Whats a good estimate of the tip

Sonbull [250]

It depends on how good the service was. it the service was really bad or just bad than maybe 2$, if the service was ok 5$ and finally if the service was extremely good and everything was just the way you like it then I would say tip 10$-20$

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3 years ago

Read 2 more answers

Here are the endpoints of the segments BC, FG, and JK. B, −67

yulyashka [42]

$~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{-6}~,~\stackrel{y_1}{7})\qquad C(\stackrel{x_2}{-4}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{[-4 - (-6)]^2 + [4 - 7]^2}\implies BC=\sqrt{(-4+6)^2+(-3)^2} \\\\\\ BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points}$

$F(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad G(\stackrel{x_2}{1}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ FG=\sqrt{[1 - (-2)]^2 + [-2 - (-4)]^2}\implies FG=\sqrt{(1+2)^2+(-2+4)^2} \\\\\\ FG=\sqrt{9+4}\implies \boxed{FG=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ J(\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad K(\stackrel{x_2}{5}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}$

$JK=\sqrt{[5 - 4]^2 + [-2 - 2]^2}\implies JK=\sqrt{1^2+(-4)^2}\implies \boxed{JK=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \overline{BC}\cong \overline{FG}~\hfill$

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1 year ago

What is the volume of a triangular pyramid that is 10 in tall and has a base area of 9 in

Andreas93 [3]

V= 1/3BH
= 1/3( 1/2x9x5)10
= 1/3(45/2) 10
= 75in ^3

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3 years ago

A 10-foot ladder is to be placed Against the side of the building. The base of the latter must be placed in an angle of 72° With

12345 [234]

Answer:

Distance of foot of ladder from building: 37.2 inches

Distance of top of ladder from building's base: 114 inches

Step-by-step explanation:

Please refer to the figure attached in the answer area.

A right angled triangle $\triangle ABC$ is formed by the ladder with the building where hypotenuse is the length of ladder.

Hypotenuse, AC = 10 foot

Also, we are given that angle made by the base of ladder with the ground is $72^\circ$ .

We have to find AB and BC.

$\angle BAC = 72^\circ$

Using trigonometric functions:

$cos \theta= \dfrac{Base}{Hypotenuse}\\cos 72^\circ= \dfrac{AB}{AC}\\\Rightarrow 0.309 = \dfrac{AB}{AC}\\\Rightarrow AB = 10 \times 0.309\\$\approx$ 3.1 foot\\$\approx$ 37.2 inches$

$sin \theta = \dfrac{Perpendicular}{Hypotenuse}\\\Rightarrow sin72^\circ = \dfrac{BC}{AC}\\\Rightarrow 0.95 = \dfrac{BC}{AC}\\\Rightarrow AB = 10 \times 0.95\\$\approx$ 9.5 foot\\$\approx$ 114 inches$

Distance of foot of ladder from building: 37.2 inches

Distance of top of ladder from building's base: 114 inches

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2 years ago