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2 years ago

Given that 3x – 4y= 22 - Find & when y = -7

Mathematics

1 answer:

Liono4ka [1.6K]2 years ago

6 0

<h2>Answer:</h2>

x=2

<h2><em><u>Step-by-step explanation:</u></em></h2>

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What is the following product? <br>(4x square root 5x^2 + 2^2 square root 6)^2

tangare [24]

The product is $104 x^{4}+16 \sqrt{30} x^{4}$

Explanation:

The given expression is $\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}$

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2$

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2$

Expanding the expression, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)$

Now, we shall apply FOIL, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}$

Simplifying the terms, we have,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}$

Multiplying, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}$

Adding the like terms, we get,

$\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}$

Thus, the product of the given expression is $104 x^{4}+16 \sqrt{30} x^{4}$

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3 years ago

What is the initial value of the exponential function shown on the graph? 7 ts O 0 1 3 O2 2 4. 7 5 4 3 2 1 1 1 2 3

Tamiku [17]

Answer:

D.(4)

Step-by-step explanation:

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2 years ago

What is a correct congruence statement for the triangles shown?

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Answer:

ΔRHS ≅ ΔNKW

Step-by-step explanation:

We are given that, in the triangles RHS and NKW.

∠H = ∠K

Side HS = KW.

∠S = ∠W

Now, using the ASA congruence criteria, which states that when two corresponding angles of the triangles are equal with the included side between them is equal, then both the triangles are congruent.

Hence, according to ASA criteria, ΔRHS ≅ ΔNKW.

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