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Ahat [919]
2 years ago
11

What is the value of b in the equation (y)*

Mathematics
1 answer:
KonstantinChe [14]2 years ago
6 0

Answer:

b = -6

Step-by-step explanation:

Apply the exponent rule that   \frac{1}{x^{n}} = x^{-n}

In this case, \frac{1}{y^{24}}  = y^{-24}

Set that equal to (y^{b})^{4}:

(y^{b})^{4} = y^{-24}

Apply the exponent rule that (x^{m})^{n} = x^{mn} so now you get:

y^{4b} = y^{-24}

Since the base is y for both sides of the equation, just set the exponents equal to each other and solve for b.

4b = -24

divide each side by 4 to get:

b = -6

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F( y ) = y + y 2 - 3
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F(y) = y + y^2 - 3

f(-2) = -2 + (-2^2) - 3
f(-2) = -2 + 4 - 3
f(-2) = -1

f(-4) = -4 + (-4^2) - 3
f(-4) = -4 + 16 - 3
f(-4) = 9

f(0) = 0 + 0^2 - 3
f(0) = -3

f(2) = 2 + 2^2 - 3
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f(2) = 3

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