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Ahat [919]
2 years ago
11

What is the value of b in the equation (y)*

Mathematics
1 answer:
KonstantinChe [14]2 years ago
6 0

Answer:

b = -6

Step-by-step explanation:

Apply the exponent rule that   \frac{1}{x^{n}} = x^{-n}

In this case, \frac{1}{y^{24}}  = y^{-24}

Set that equal to (y^{b})^{4}:

(y^{b})^{4} = y^{-24}

Apply the exponent rule that (x^{m})^{n} = x^{mn} so now you get:

y^{4b} = y^{-24}

Since the base is y for both sides of the equation, just set the exponents equal to each other and solve for b.

4b = -24

divide each side by 4 to get:

b = -6

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QUESTION IS DOW BELOW 30 POINTS EACH PLEASE HELP PLEASE HELP PLEASE HELP
ivann1987 [24]

The required solution is ∠RQT =  202°  and ∠QTS = 51°

<h3 />

<h3>What is a cyclic quadrilateral?</h3>

A cyclic quadrilateral is a quadrilateral which has all its four vertices lying on a circle. It is also called as inscribed quadrilateral.

Its main property is that the sum of opposite angles of inscribed quadrilateral is always 180 degrees.

Now, the given circle has a cyclic quadrilateral QRST in which it is given that  ∠RQT =  202° and ∠QRS = 129°

Since,sum of the opposite angles of a cyclic quadrilateral =  180°  

⇒∠QTS + ∠QRS = 180°

⇒ ∠QTS  + ∠129° = 180°

⇒ ∠QTS = 180° - ∠129°

⇒ ∠QTS = 51°

Hence,the requires angles are ∠RQT =  202° and ∠QTS = 51°.

More about cyclic quadrilateral :

brainly.com/question/14323008

#SPJ1

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