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3 years ago

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if an object is being pulled by two forces, one 4n to the left, and the other 2 n to the right, what is the net force acting on

the object?

1 answer:

Naddika [18.5K]3 years ago

6 0

Answer:

2 N to the left

Explanation:

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HOLA, NECESITO AYUDA!

givi [52]

The electrostatic force between the two ions is $2.9\cdot 10^{-10} N$

Explanation:

The electrostatic force between two charged particle is given by Coulomb's law:

$F=k\frac{q_1 q_2}{r^2}$

where

$k=8.99\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

$q_1, q_2$ are the two charges

r is the separation between the two charges

In this problem, the ion of sodium has a charge of

$q_1 = +e = +1.6\cdot 10^{-19} C$

while the ion of chlorine has a charge of

$q_2 = -e = -1.6\cdot 10^{-19}C$

And the distance between the two ions is

$r=282 pm = 282\cdot 10^{-12} m$

Substituting, we find the electrostatic force between the two ions:

$F=(8.99\cdot 10^9) \frac{(1.6\cdot 10^{-19})(-1.6\cdot 10^{-19})}{(282\cdot 10^{-12})^2}=-2.9\cdot 10^{-10} N$

where the negative sign simply means that the force is attractive, since the two ions have opposite charge.

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The answer is D.nitrogen. the atmosphere is mostly made up of nitrogen.(95% is nitrogen) and (2% <span>oxygen</span>) and and (3% of other gases)

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You are the captain of a pirate ship and wish to find out how strong a new first mate is at rowing treasure from shore to the sh

Kryger [21]

The formula that is usually used for the calculation of power is the product of force applied and the speed at which the action is done. That is,
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3 years ago

You pull a suitcase along the floor by exerting 43N at an angle. The force of friction is 27 N and the suitcase moves at a const

Mumz [18]

The angle of the force is $51.1^{\circ}$

Explanation:

To solve this problem, we can apply Newton's second law along the horizontal direction of motion of the suitcase:

$\sum F_x = ma_x$

where

$\sum F_x$ is the net force along the x-axis

m is the mass of the suitcase

$a_x$ is the acceleration along the x-axis

The suitcase is moving at constant speed, so the acceleration is zero:

$a_x=0$

Therefore the net force must also be zero:

$\sum F_x = 0$ (1)

We have two forces acting along the horizontal direction:

- The component of the push (forward) in the horizontal direction, $F cos \theta$ , with

F = 43 N

$\theta$ = angle of the force with the horizontal

- The force of friction, $F_f = 27 N$ , backward

So the net force can be written as

$\sum F_x = F cos \theta - F_f$ (2)

Combining (1) and (2),

$F cos \theta - F_f = 0$

And so we can find the angle:

$\theta = cos^{-1}(\frac{F_f}{F})=cos^{-1}(\frac{27}{43})=51.1^{\circ}$

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3 years ago