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Amiraneli [1.4K]
3 years ago
12

2 rocks of the same mass are rolling down a hill at different speeds (one faster than the other). which rick would have more kin

etic energy??
Physics
2 answers:
stepan [7]3 years ago
5 0

Kinetic energy of an object depends on its mass and its speed.

If the masses are equal, then the rick with <em>more speed</em> has more kinetic energy.

Sedbober [7]3 years ago
4 0

The rock which is faster than the other have more kinetic energy.

<u>Explanation:</u>

Two rocks are of same mass are rolled down the hill at different speeds. Before the rocks are rolled, at rest they both will have same potential energy and zero kinetic energy. When the rocks are rolled, their potential energy reduces as they move forward and their kinetic energy increases from zero.

Since they are travelling at different speeds, one will be faster than the other, and so one rock reached faster than the other. The rock which reaches the ground first will have more kinetic energy than the other.

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At the end of a race a runner decelerates from a velocity of 8.90 m/s at a rate of 1.70 m/s2. (a) How far in meters does she tra
Ad libitum [116K]

Answer:

x=22.33m

Explanation:

Kinematics equation for constant deceleration:

x =v_{o}*t - 1/2*at^{2}=8.9*6.3-1/2*1.70*6.3^{2}=22.33m

7 0
3 years ago
Rewire each of the following using the correct prefix using 2 decimal places where applicable.
Ede4ka [16]

Answer:

a. 1.2×10^-6

b. 0.42×10^9

c. 246.8×10^3

d. 88

3 0
3 years ago
The blades in a blender rotate at a rate of 6100 rpm. When the motor is turned off during operation, the blades slow to rest in
MissTica

Answer:

<em>155.80rad/s</em>

Explanation:

Using the equation of motion to find the angular acceleration:

\omega_f = \omega_i + \alpha t

\omega_f is the final angular velocity in rad/s

\omega_i  is the initial angular velocity in rad/s

\alpha is the angular acceleration

t is the time taken

Given the following

\omega_f = 6100rpm

Time = 4.1secs

Convert the angular velocity to rad/s

1rpm = 0.10472rad/s

6100rpm = x

x = 6100 * 0.10472

x  = 638.792rad/s

\omega_f = 638.792rad/s\\

Get the angular acceleration:

Recall that:

\omega_f = \omega_i + \alpha t

638.792 = 0 + ∝(4.1)

4.1∝ = 638.792

∝ = 638.792/4.1

∝ = 155.80rad/s

<em>Hence the angular acceleration as the blades slow down is 155.80rad/s</em>

5 0
3 years ago
A light, rigid rod is 55.8 cm long. Its top end is pivoted on a frictionless horizontal axle. The rod hangs straight down at res
VMariaS [17]

To solve this problem we will apply the principle of conservation of energy. For this purpose, potential energy is equivalent to kinetic energy, and this clearly depends on the position of the body. In turn, we also note that the height traveled is twice that of the rigid rod, therefore applying these concepts we will have

KE = PE

\frac{1}{2} mv^2 = mgh

v = \sqrt{2gh}

v = \sqrt{2(9.8)(2(55.8*10^{-2}))}

v = 4.67m/s

Therefore the minimum speed at the bottom is required to make the ball go over the top of the circle is 4.67m/s

4 0
3 years ago
What is the difference between beta plus and minus
Minchanka [31]
Beta decay is very complex phenomena in natural radioactive decay. There are 3 types of Beta decay.

B+ decay (Beta plus or Beta positive or positron decay):

is the conversion of a proton into a neutron plus a positron and an electron neutrino.

B- decay (Beta negative or Beta nought):

is the conversion  of a neutron into a proton plus an electron and a electron antineutrino. 

Note: a positron is the a positive electron or the antiparticle of the electron.

Hope it helps
7 0
3 years ago
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