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pishuonlain [190]
3 years ago
13

A stone is dropped from a bridge and hits the pavement below in two seconds. What is the velocity of the stone when it hits the

pavement?
A. 0.20 m/s
B. 19.6 m/s
C. 4.9 m/s
D. 9.8 m/s
Physics
2 answers:
Helen [10]3 years ago
4 0
We have: a = v/t
Here, t = 2 s  [ Given ]
a = 9.8 m/s²  [constant value for earth system ]

Substitute their values into the expression:
9.8 = v/2
v = 9.8 × 2
v = 19.6 m/s

In short, Your Answer would be Option B

Hope this helps!
Yakvenalex [24]3 years ago
4 0

i just did the quiz and so the only 2 options that made logical sense would be B (19.6 m/s) or D (9.8 m/s) the reason someone could get confused between these two is because 19.6 divided by 2 is 9.8 m/s so for each second it will go down 9.8 m/s but since it wants to know the velocity it would be 19.6 m/s

hope this helps

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A body is oscillating up and down at the end of a spring. Let’s consider when the body is at the top of its up-and-down motion.
Klio2033 [76]

The velocity of the body is zero; option A

<h3>What is the motion of an oscillating body?</h3>

The motion of an oscillating body is known as simple harmonic motion.

Simple harmonic motion involves a periodical motion of a body whose acceleration is directed towards a fixed point.

For a body that is oscillating up and down at the end of a spring, considering when the body is at the top of its up-and-down motion, the velocity of the body at the top and down is zero since the body comes to rest at the top and down position of its motion.

In conclusion, oscillating bodies undergo simple harmonic motion.

Learn more about simple harmonic motion at: brainly.com/question/24646514

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3 0
1 year ago
A girl of mass 55 kg throws a ball of mass 0.80 kg against a wall. The ball strikes the wall horizontally with a speed of 25 m/s
lisabon 2012 [21]

Answer:

Magnitude of the average force exerted on the wall by the ball is 800N

Explanation:

Given

Contact Time = t = 0.05 seconds

Mass (of ball) = 0.80kg

Initial Velocity = u = 25m/s

Final Velocity = 25m/s

Magnitude of the average force exerted on the wall by the ball is given by;

F = ma

Where m = 0.8kg

a = Average Acceleration

a = (u + v)/t

a = (25 + 25)/0.05

a = 50/0.05

a = 1000m/s²

Average Force = Mass * Average Acceleration

Average Force = 0.8kg * 1000m/s²

Average Force = 800kgm/s²

Average Force = 800N

Hence, the magnitude of the average force exerted on the wall by the ball is 800N

3 0
3 years ago
Use the following half-life graph to answer the following question:
Temka [501]

Answer:

A 1.0 min

Explanation:

The half-life of a radioisotope is defined as the time it takes for the mass of the isotope to halve compared to the initial value.

From the graph in the problem, we see that the initial mass of the isotope at time t=0 is

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The half-life of the isotope is the time it takes for half the mass of the sample to decay, so it is the time t at which the mass will be halved:

m'=\frac{50.0 g}{2}=25.0 g

We see that this occurs at t = 1.0 min, so the half-life of the isotope is exactly 1.0 min.

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