Answer:
protect equipment by stopping the flow of electric current; protect your house from fire.
First, we will get the distance traveled before the driver applied the brakes.
distance = velocity * time
distance = 25*0.34 = 8.5 m
Now, we will calculated the distance that the car traveled after the driver applied the brakes. To do this, we will use the equation of motion:
<span>vf^2 = vi^2 + 2*a*d where:
</span>vf = zero, vi = 25 m/s and a = -7 m/s^2
Note: The negative sign is only to show deceleration
d = <span> 1/2*(625) /(7) = 44.6428 m
The total stopping distance =</span> 8.5 + 44.6428 = 53.1428 m
Answer:
1.63 N
Explanation:
F = GMm/r^2
= (6.67x10^-11)(10x10^5)(3x10^5) / 3.5^2
= 1.63 N ( 3 sig. fig.)
Answer:
Approximately 
.
Explanation:
Assuming that there is no other force on this vehicle, the 
force from the road would be the only force on this vehicle. The net force would then be equal to this 
force. The size of the net force would be 
.
Let 
denote the mass of this vehicle and let 
denote the net force on this vehicle.
By Newton's Second Law of motion, the acceleration of this vehicle would be proportional to the net force on this vehicle. In other words, the acceleration of this vehicle, 
, would be:
.
For this vehicle, 
whereas 
. The acceleration of this vehicle would be:
.
He should a step-up transformer with k=220/120=1.83 so output coil must have 240*1.83=440 turns
