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mojhsa [17]
3 years ago
15

(-w-6)/(w^2+4w-12), how do i write this into simplest form?

Mathematics
1 answer:
PIT_PIT [208]3 years ago
7 0
First factorise the top = -(w+6)
The first factorise the bottom: (w^2 + 4w -12) = (w+6) (w-2)
Therefore the two (w+6) cancels out and you are left with -1 / w-2
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Z^2 -6z+9=0 Factor and solve
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Factor because if we have
yz=0 then we can assume y and/or z=0

so factor
so the easiest way is to find what 2 numbers add to -6 and multiply to get 9 so
we know that they must be both - because we must have x+x=(-) and x^2=+ so therefor they must be negative
factors of 9=3 and 3 so
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(z-3)(z-3)=0

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add 3
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2 years ago
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3 years ago
Dion builds a pattern that is represented by the equation b equals 2 F + 6 where f is the figure number of the pattern and B is
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Step-by-step explanation:

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3 years ago
Find the center of the circle that you can circumscribe about DABC.
Vlada [557]

The center of the circle that circumscribe about DABC is (h,k) = (1, 5).

A circle can be modelled after a expression of the form:

A\cdot x + B\cdot y + C =-x^{2}-y^{2} (1)

We can determine all coefficients by knowing three <em>distinct</em> points on plane.

If we know that (x_{1}, y_{1}) = (2, 8), (x_{2}, y_{2}) = (0, 8) and (x_{3}, y_{3}) = (2, 2), then the solution of the system of linear equations is:

2\cdot A + 8\cdot B + C = -68 (2)

8\cdot B + C = -64 (3)

2\cdot A + 2\cdot B + C = -8 (4)

A = -2, B = -10, C = 16

Now we proceed to <em>complete</em> squares and factor each resulting perfect square trinomial in order to determine the coordinates of the center of the circle:

x^{2}+y^{2}-2\cdot x -10\cdot y +16 = 0

(x^{2}-2\cdot x +1)-1+(y^{2}-10\cdot y +25)-25 +16 = 0

(x-1)^{2}+(y-5)^{2}= 10

The center of the circle that circumscribe about DABC is (h,k) = (1, 5).

To learn more on circles, we kindly invite to check this verified question: brainly.com/question/11833983

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