Answer:
方法/步骤
右键单击以选择此计算机，然后有一个菜单来选择属性。
选择后，打开属性面板以找到我们的高级系统设置。
打开后，我们在系统设置下找到高级设置。
打开后，我们看到下面有一个环境变量选项。
打开后，我们在右下角看到一个删除选项。
单击删除到，在右下角后单击删除，然后单击确定的选项。 ...
本文未经授权摘自百度经验
D. A spike of electricity. They are fast and have a short duration.
Answer:
1111000
Explanation:
perform the following. write from right to left:
- is the number even? then write down a 0
- is the number odd? then write down a 1 and subtract 1
- divide by 2
- repeat until you reach 0.
So for 120:
120 is even, so write down a 0 and continue with 120/2=60
60 is even, so write down a 0 and continue with 60/2=30
30 is even, so write down a 0 and continue with 30/2=15
15 is odd, so write down a 1 and continue with 14/2=7
7 is odd, so write down a 1 and continue with 6/2=3
3 is odd, so write down a 1 and continue with 2/2=1
1 is odd, so write down a 1 and finish with 0
<span> Jason can use the filter tool to edit while maintaining the original content of the file.</span>
Answer:
#include<stdio.h>
#include <iostream>
using namespace std;
int main(){
int number, min, max;
cout << "Enter the minimum range: ";
cin >> min;
cout << "Enter the maximum range: ";
cin >> max;
cout << "Odd numbers in given range are: ";
for(number = min; number <= max; number++)
if(number % 2 !=0)
cout << number<< " ";
cout<< "Even numbers in given range are: ";
for(number = min; number <= max; number++)
if(number % 2 ==0)
cout << number << " ";
return 0;
}
Explanation:
First of all, we take declare two variables. one as the lowest number of the range and the other as the upper limit of the range (in this case: <em>min</em> and <em>max</em>). We declare another variable (<em>number</em>) and store in it the lowest number of the range (<em>min</em>). To check whether the number currently stored as the value of the variable (<em>number</em>) is even, we take in account the remainder of that number divided by 2. If the remainder does not equals 0, we print that number as odd. We again check the remainder by dividing the number by 2. If the remainder does equals 0, we print that number as even.
