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stealth61 [152]
2 years ago
12

If 14x + 5 = 12, what is the value of x?

Mathematics
1 answer:
ser-zykov [4K]2 years ago
6 0
<h3>x = 1/2</h3>

Step-by-step explanation:

14x + 5 = 12

14x = 12 - 5

14x = 7

x = 7/14

x = 1/2

<h3>Hope it helps you!!</h3>
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6.66666667E-5

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Given z1 = 2 +StartRoot 3 EndRoot i and z2 = 1 – StartRoot 3 EndRoot i, what is the sum of z1 and z2?
Fofino [41]

Answer:

z1 + z2 = 3

Step-by-step explanation:

Since we are given z1 = 2 + √(3)i and z2 = 1 – √(3)i. The sum of z1 + z2 would be:

(2 + √(3)i) + (1 – √(3)i) = 2 + √(3)i + 1 – √(3)i = 2 + 1 + √(3)i – √(3)i = 3

Hence, z1 + z2 = 3.

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3 years ago
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Find all solutions to
BARSIC [14]

Answer:

x= 0 , \frac{1}{14} , \frac{-1}{12}

Step-by-step explanation:

Given, equation is \sqrt[3]{15x-1} + \sqrt[3]{13x+1} = 4\sqrt[3]{x}. →→→ (1)

Now, by cubing the equation on both sides, we get

( \sqrt[3]{15x-1} + \sqrt[3]{13x+1} )³ = (4\sqrt[3]{x})³

⇒ (15x-1) + (13x+1) + 3×\sqrt[3]{15x-1}×\sqrt[3]{13x+1} (\sqrt[3]{15x-1} + \sqrt[3]{13x+1}) = 64 x.

⇒ 28x + 3×\sqrt[3]{15x-1}×\sqrt[3]{13x+1} (4\sqrt[3]{x}) = 64x.        

(since from (1),  \sqrt[3]{15x-1} + \sqrt[3]{13x+1} = 4\sqrt[3]{x})

⇒ 12× \sqrt[3]{15x-1}×\sqrt[3]{13x+1} (\sqrt[3]{x})= 36x.

⇒ 3x = \sqrt[3]{(15x-1)(13+1)(x)}.

Now, once again cubing on both sides, we get

(3x)³ = (\sqrt[3]{(15x-1)(13+1)(x)})³.

⇒ 27x³ = (15x-1)(13x+1)(x).

⇒ 27x³ = 195x³ + 2x² - x

⇒ 168x³ + 2x² - x = 0

⇒ x(168x² + 2x -1) = 0

⇒ by, solving the equation we get ,

x = 0 ; x = \frac{1}{14} ; x = \frac{-1}{12}

therefore, solution is x= 0 , \frac{1}{14} , \frac{-1}{12}

7 0
3 years ago
Can anyone help me?
Ray Of Light [21]
Y = √(-x + 3)
Domain: x ≤ 3

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