Answer:
t = 6179.1 s = 102.9 min = 1.7 h
Explanation:
The energy provided by the resistance heater must be equal to the energy required to boil the water:
E = ΔQ
ηPt = mH
where.
η = efficiency = 84.5 % = 0.845
P = Power = 2.61 KW = 2610 W
t = time = ?
m = mass of water = 6.03 kg
H = Latent heat of vaporization of water = 2.26 x 10⁶ J/kg
Therefore,
(0.845)(2610 W)t = (6.03 kg)(2.26 x 10⁶ J/kg)
<u>t = 6179.1 s = 102.9 min = 1.7 h</u>
Answer:
i am pretty sure it is scientific method
Explanation:
because you can search up what is scientific method and it will show 7 steps of it thank me plz
Answer:
1.75 kW
$0.137 kWh
4.61 kW
$3.16 therm
Explanation:
Utilized power input of the burner is
P(ui) = total power input * efficiency
P(ui) = 2400 W * 0.73
P(ui) = 1752 W or 1.75 kW
Unit cost of utilized energy is
C(ui) = Unit cost of electricity/efficiency
C(ui) = $0.1 / 0.73 kWh
C(ui) = $0.137 kWh
Power input to the gas burner is
P(gi) = Utilized power input of the burner / efficiency of the burner
P(gi) = 1.75 / 0.38
P(gi) = 4.61 kW
Unit cost of utilized energy is
C(gi) = Unit cost of gas /efficiency
C(gi) = $1.2 / 0.38 kWh
C(gi) = $3.16 therm
Answer:
see explaination
Explanation:
Module VBModule
Function KineticEnergy(ByVal mass As Decimal, ByVal velocity As Decimal) As Decimal
Dim result As Decimal
result = 0.5*mass*velocity*velocity
KineticEnergy = result
End Function
Sub Main()
Dim mass = Console.ReadLine()
Dim velocity = Console.ReadLine()
Console.WriteLine(FormatNumber(CDbl(KineticEnergy(mass,velocity)), 3))
End Sub
End Module