Answer:
t= 9.79 hr
Explanation:
Given that
V= 3.5 V
Capacity= 4 Amp-hour
We know that
V= IR
V= Voltage
I =Current
R=Resistance
V = I R
The total voltage on the batteries will be 2 V
2 x 3.5 = I x 10
I= 0.7 A
We know that Power P
P = V I
P = 0.7 x 7
P =4.9 W
4 A.h and 12 volt power supply = 4 x 12 = 48 W.hr
So time of drain t
4.9 t = 48
t= 9.79 hr
Answer:
I would say false but I am not for sure
Answer:
Explanation:
requires U.S. government programs to use SI units - Treaty of the Meter
advisory panel to consider the feasibility of adopting the metric system - Metric Conversion Act
established a uniform and standardized metric system - U.S Metric Study
I might be wrong though
Answer:
T=833.8 °C
Explanation:
Given that
m= 2 kg
T₁=200 °C
time ,t= 10 min = 600 s
Work input = 1 KW
Work input = 1 x 600 KJ=600 KJ
Heat input = 0.5 KW
Q= 05 x 600 = 300 KJ
Gas is ideal gas.
We know that for ideal gas internal energy change given as
ΔU= m Cv ΔT
For air Cv= 0.71 KJ/kgK
From first law of thermodynamics
Q = ΔU +W
Heat input taken as positive and work in put taken as negative.
300 KJ = - 600 KJ + ΔU
ΔU = 900 KJ
ΔU= m Cv ΔT
900 KJ = 2 x 0.71 x (T- 200 )
T=833.8 °C
So the final temperature is T=833.8 °C