Answer:
Force per unit plate area is 0.1344 ![N/m^{2}](https://tex.z-dn.net/?f=N%2Fm%5E%7B2%7D)
Solution:
As per the question:
The spacing between each wall and the plate, d = 10 mm = 0.01 m
Absolute viscosity of the liquid, ![\mu =1.92\times 10^{- 3} Pa-s](https://tex.z-dn.net/?f=%5Cmu%20%3D1.92%5Ctimes%2010%5E%7B-%203%7D%20Pa-s)
Speed, v = 35 mm/s = 0.035 m/s
Now,
Suppose the drag force that exist between each wall and plate is F and F' respectively:
Net Drag Force = F' + F''
![F = \tau A](https://tex.z-dn.net/?f=F%20%3D%20%5Ctau%20A)
where
= shear stress
A = Cross - sectional Area
Therefore,
Net Drag Force, F = ![(\tau ' +\tau '')A](https://tex.z-dn.net/?f=%28%5Ctau%20%27%20%2B%5Ctau%20%27%27%29A)
![\frac{F}{A} = \tau ' +\tau ''](https://tex.z-dn.net/?f=%5Cfrac%7BF%7D%7BA%7D%20%3D%20%5Ctau%20%27%20%2B%5Ctau%20%27%27)
Also
F = ![\frac{\mu v}{d}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cmu%20v%7D%7Bd%7D)
where
= dynamic coefficient of viscosity
Pressure, P = ![\frac{F}{A}](https://tex.z-dn.net/?f=%5Cfrac%7BF%7D%7BA%7D)
Therefore,
![\frac{F}{A} = \frac{\mu v}{d} + \frac{\mu v}{d} = 2\frac{\mu v}{d}](https://tex.z-dn.net/?f=%5Cfrac%7BF%7D%7BA%7D%20%3D%20%5Cfrac%7B%5Cmu%20v%7D%7Bd%7D%20%2B%20%5Cfrac%7B%5Cmu%20v%7D%7Bd%7D%20%3D%202%5Cfrac%7B%5Cmu%20v%7D%7Bd%7D)
![\frac{F}{A} = 2\frac{1.92\times 10^{- 3}\times 0.035}{0.010} = 0.01344 N/m^{2}](https://tex.z-dn.net/?f=%5Cfrac%7BF%7D%7BA%7D%20%3D%202%5Cfrac%7B1.92%5Ctimes%2010%5E%7B-%203%7D%5Ctimes%200.035%7D%7B0.010%7D%20%3D%200.01344%20N%2Fm%5E%7B2%7D)
Answer:
to optimize the reliability of equipment and infrastructure;
- to ensure that equipment and infrastructure are always in good condition;
- to carry out prompt emergency repair of equipment and infrastructure so as to secure the best possible availability for production;
- to enhance, through modifications, extensions, or new low-cost items, the productivity of existing equipment or production capacity;
- to ensure the operation of equipment for production and for the distribution of energy and fluids;
- to improve operational safety;
- to train personnel in specific maintenance skills;
- to advise on the acquisition, installation and operation of machinery;
- to contribute to finished product quality;
- to ensure environmental protection.
Explanation:
pick whichever you want
Answer:
874 psi
Explanation:
Given a sample mean (x') = 900,
and a standard error (SE) = 10
At 99% confidence, Z(critical) = 2.58
That gives 99% confidence interval as,
x' ± Z(critical) x SE = 900 ± 2.58 x 10
The value of the lower limit is,
900 - 25.8 = 874.2
≈ 874 psi
Answer:
a) 4.7 kΩ, +/- 5%
b) 2.0 MΩ, +/- 20%
Explanation:
a) If the resistor has the following combination of color bands:
1) Yellow = 1st digit = 4
2) Violet = 2nd digit = 7
3) Red = multiplier = 10e2
4) Gold = tolerance = +/- 5%
this means that the resistor has 4700 Ω (or 4.7 kΩ), with 5% tolerance.
b) Repeating the process for the following combination of color bands:
1) Red = 1st digit = 2
2) Black = 2nd digit = 0
3) Green = multiplier = 10e5
4) Nothing = tolerance = +/- 20%
This combination represents to a resistor of 2*10⁶ Ω (or 2.0 MΩ), with +/- 20% tolerance.