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3 years ago

13

Christopher has designed a fluid power system that repeatedly gets clogs. Which of the following objects should he choose to add

to his fluid power system to prevent these clogs in the future?
filter

pipe

valve

piston

1 answer:

MA_775_DIABLO [31]3 years ago

3 0

Answer:

Valve

Explanation:

Its right

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An ideal Rankine cycle with reheat uses water as the working fluid. The conditions at the inlet to the first-stage turbine are p

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3 years ago

1. What is an op-amp? List the characteristics of an ideal op-amp

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Answer:

An opamp is an operation amplifier. It takes an input signal and amplifies it on the output side.

An ideal opamp should have infinite impedance at its input, infinite gain on the output, and zero impedance on the output

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3 years ago

9) A construction company employs 2 sales engineers. Engineer 1 does the work in estimating cost for 70% of jobs bid by the comp

Irina18 [472]

The probability that the error occurred when Engineer 2 made the mistake is 0.462 on the other hand the probability that the error occurred when the engineer 1 made the mistake is 0.538

Explanation:

Let $E_{1}$ denote the event that the 1st engineer does the work.so we write

$P(E)_{1}$ =0.7

Let $E_{2}$ denote the event that the 2nd engineer does the work .So we write

$P(E)_{2}$ =0.3

Let O denote the event during which the error occurred .so we write

$P(O/E_{1} )$ =0.02(GIVEN)

$P(O/E_{2} )$ =0.04(GIVEN)

The probability that the error occurred when the first engineer performed the work is $P(E_{1} /O)$

The probability that the error occurred when the first engineer performed the work is $P(E_{2} /O)$

Now we need to find when did the error in the work occur so we will compare the probability of the work done by <u>engineer 1 </u>and <u>engineer 2 </u>

<u></u>

<u>lets find the Probability of the Engineer 1</u>

<u>Using Bayes theorem,we get</u>

<u></u>

<u></u> $P(E_{1} /O)$ =0.02*0.7/0.02*0.7+0.04*0.3 = 0.014/0.026=0.538

<u>lets find the Probability of the Engineer 2</u>

<u></u> $P(E_{2} /O)$ =0.04*0.3/0.02*0.7+0.04*0.3=0.012/0.026=0.462

Since ,0.462<0.538 so it is more prominent that the Engineer 1 did the work when the error occurred

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3 years ago

The components of an electronic system dissipating 180 W are located in a 1-m-long horizontal duct whose cross section is 16 cm

oee [108]

Answer:

a) The exit temperature is 39.25°C

b) The highest component surface is 132.22°C

c) The average temperature for air equal to 35°C is a good assumption because the air temperature at the inlet will increase due to the result in the heat gain produced by the duct and whose surface is exposed to a flow of hot.

Explanation:

a) The properties of the air at 35°C:

p = density = 1.145 kg/m³

v = 1.655x10⁻⁵m²/s

k = 0.02625 W/m°C

Pr = 0.7268

cp = 1007 J/kg°C

a) The mass flow rate of air is equal to:

$m=\rho *V = 1.145*0.65=0.7443kg/min=0.0124kg/s$

The exit temperature is:

$T=T_{i} +\frac{Q}{m*c_{p} } =27+\frac{0.85*180}{0.0124*1007} =39.25$ °C

b) The mean fluid velocity is:

$V_{m} =\frac{V}{A} =\frac{0.65}{0.16*0.16} =25.4m/min=0.4232m/s$

The hydraulic diameter is:

$D_{h} =\frac{4A}{p} =\frac{4*0.16*0.16}{4*0.16} =0.16m$

The Reynold´s number is:

$Re=\frac{VD_{h} }{v} =\frac{0.4232*0.16}{1.655x10^{-5} } =4091.36$

Assuming fully developed turbulent flow, the Nusselt number is:

$Nu=0.023Re^{0.8} *Pr^{0.4} =0.023*4091.36^{0.8} *0.7268^{0.4} =15.69$

$h=\frac{k*Nu}{D_{h} } =\frac{0.02625*15.69}{0.16} =2.57W/m^{2} C$

The highest component surface temperature is:

$T=T_{e} +\frac{\frac{Q}{A} }{h} =39.2+\frac{0.85*\frac{180}{4*0.16*1} }{2.57} =132.22$ °C

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3 years ago

Who was the American founder and leader of the Shakers in the 1770’s who advocated equality, individual responsibility, and peac

DaniilM [7]

Answer: Ann Lee (1736-1784)

Explanation:

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3 years ago

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