Answer:
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Explanation:
Answer:
Explanation:
a )
pH = - log[ H⁺]
8.26 = - log[ H⁺]
[ H⁺] = 10⁻⁸°²⁶ mole / l
= 5.49 x 10⁻⁹ moles / l
[ H⁺] [OH⁻] = 10⁻¹⁴
[OH⁻] = 10⁻¹⁴ / 5.49 x 10⁻⁹
= .182 x 10⁻⁵ moles / l
b )
10.25 = - log[ H⁺]
[ H⁺] = 10⁻¹⁰°²⁵ mole / l
= 5.62 x 10⁻¹¹ moles / l
[ H⁺] [OH⁻] = 10⁻¹⁴
[OH⁻] = 10⁻¹⁴ / 5.62 x 10⁻¹¹
= .178 x 10⁻³ moles / l
c )
4.65 = - log[ H⁺]
[ H⁺] = 10⁻⁴°⁶⁵ mole / l
= 2.24 x 10⁻⁵ moles / l
[ H⁺] [OH⁻] = 10⁻¹⁴
[OH⁻] = 10⁻¹⁴ / 2.24 x 10⁻⁵
= .4464 x 10⁻⁹ moles / l
D the strength of both acid and base
To
determine the volume of both concentration of the solution to make another concentration of solution, we need to set up
two equations since we have two unknowns. <span>
For the first equation, we do a mass balance:
mass of 50% solution + mass of 20% solution =
mass of 40% solution
M1 + M2 = M3
For the second equation, we do a component balance,</span>
<span>
M1(50%) + M2(20%) = M3(40%)
.50M1 + .20M2 = .40M3
To determine the ratio, we assume we have to make a 100 g of the 40% solution. So, the equation would change to</span>
<span>
</span>
<span>M1 + M2 = 100</span>
.50M1 + .20M2 = (100)(.40) = 40
Solving for M1 and M2,
M1 = 66.67 g
M2 = 33.33 g
So, the ratio of the 20% and the 50% would be approximately 33.33/66.67 = 0.5.