Molecules can be described as
1 answer:
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I searched for complete question (as your question is missing with structure) and found the structure of compound attached below.
Answer:
The compound can neither act as a Hydrogen Bond Donor nor act as a Hydrogen Bond Acceptor.
Explanation:
For two compounds to build Hydrogen Bond Interactions it is compulsory that they must contain Hydrogen atoms which are directly attached to most electronegative atoms like Fluorine, Oxygen and Nitrogen.
As the given compound is 2-Butene (a non polar hydrocarbon), it lacks partial positive Hydrogen (which can act as Hydrogen Bond Donor) and a most electronegative element (F, O or N) which can act as Hydrogen Bond Acceptor. Therefore, this compound will not generate any Hydrogen Bonding with water molecules and will remain immiscible in it.
Answer:
The compound can neither act as a Hydrogen Bond Donor nor act as a Hydrogen Bond Acceptor.
Explanation:
For two compounds to build Hydrogen Bond Interactions it is compulsory that they must contain Hydrogen atoms which are directly attached to most electronegative atoms like Fluorine, Oxygen and Nitrogen.
As the given compound is 2-Butene (a non polar hydrocarbon), it lacks partial positive Hydrogen (which can act as Hydrogen Bond Donor) and a most electronegative element (F, O or N) which can act as Hydrogen Bond Acceptor. Therefore, this compound will not generate any Hydrogen Bonding with water molecules and will remain immiscible in it.
Answer: The vapor pressure of water at 298 K is 3.565kPa.
Explanation:
The vapor pressure is determined by Clausius Clapeyron equation:
where,
= initial pressure at 298 K = ?
= final pressure at 373 K = 101.3 kPa
= enthalpy of vaporisation = 41.1 kJ/mol = 41100 J/mol
R = gas constant = 8.314 J/mole.K
= initial temperature = 298 K
= final temperature = 373 K
Now put all the given values in this formula, we get
Therefore, the vapor pressure of water at 298 K is 3.565kPa.