The correct formula for sodium oxide is?

The law of universal gravitation states that any two objects in the universe, without exception, a. attract each other. b. repel

insens350 [35]

Newton's law of universal gravitation states that a particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers. Using this law the answer will be A. attract each other.

5 0

2 years ago

If 1,000 mL = 1 L, which of the following are possible conversion factors for liters and milliliters? Check all that apply.

Fudgin [204]

Answer:

Two conversion factors:

$1=\dfrac{1L}{1,000ml}\\ \\ \\ 1=\dfrac{1,000mL}{1L}$

Explanation:

You can create two possible conversion factors, one to convert from mL to L, and one to convert from L to mL

a) From mL to L

To convert mL to L you need to multiply by a conversion factor that has mL on the denominator and L in the numerator.

Your starting point is: $1,000mL=1L$

Then, divide both sides by 1,000mL (this will be on the denominator of the fraction);

$1,000mL=1L\\\\ \\\dfrac{1,000ml}{1,000mL}=\dfrac{1L}{1,000mL}\\ \\ \\ 1=\dfrac{1L}{1,000mL}$

b) From L to mL

Divide both sides by 1 L:

$1,000mL=1L\\\\ \\\dfrac{1,000ml}{1L}=\dfrac{1L}{1L}\\ \\ \\ 1=\dfrac{1,000mL}{1L}$

7 0

2 years ago

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The heat of vaporization of 1–pentanol is 55.5 kJ/mol, and its entropy of vaporization is 148 J/K•mol. What is the approximate b

tensa zangetsu [6.8K]

Answer:

375 K

Explanation:

Using the experssion shown below as:

$\Delta G^0=\Delta H^0_{vap}-T\Delta S^0_{vap}$

At vaporization point, the liquid and the gaseous phase is in the equilibrium.

Thus,

$\Delta G^0=0$

So,

$Delta H^0_{vap}=T\Delta S^0_{vap}$

Given that:

$Delta H^0_{vap}=55.5\ kJ/mol$

Also, 1 kJ = 10³ J

So,

$Delta H^0_{vap}=55500\ J/mol$

$\Delta S^0_{vap}=148\ J/K.mol$

So, temperature is :

$T=\frac{Delta H^0_{vap}}{\Delta S^0_{vap}}$

$T=\frac{55500}{148}$

T= 375 K

3 0

3 years ago

If a combination reaction takes place between rubidium and bromine, the chemical formula for the product is

lesya [120]

The chemical formula for the product is RbBr.

7 0

2 years ago

Suppose you were to make a ring from a single strand of gold atoms. How many gold atoms would be required to make such a ring? H

Rudiy27

Let us assume that the ring is a size 7 ring, which has a circumference of 54.3 millimeters. Converting this to centimeters, the circumference of the ring is:

54.3 mm = 5.43 cm

Now, we determine the number of gold atoms that will be present in this:

5.43 / 1 x 10⁻⁹

There will be 5.43 x 10⁹ atoms

We now determine the number of moles this is by:

one mole = 6.02 x 10²³ atoms

Moles = 5.43 x 10⁹ / 6.02 x 10²³
Moles = 9.01 x 10⁻¹⁵ moles

The molar mass of gold is 197 g/mol

The mass is 9.01 x 10⁻¹⁵ * 197

The mass of the strand is 1.76 x 10⁻¹² grams

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2 years ago

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