If cot 0=12/5 find tan 0
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Let p be 0.831 denote the percentage of defective welds and q be 0.169 denote the percentage of non-defective welds.
Using the binomial distribution, we want all three to be defective.
Using the binomial distribution, we want all three to be defective.
Answer:
Area = 1500
Step-by-step explanation:
Area= height ×(Base 1 +base 2)
Area = 20 × (40+35)
Area = 20×75
Area = 1500