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jolli1 [7]
3 years ago
5

Evalute the piecewise function for the given values of x​

Mathematics
1 answer:
podryga [215]3 years ago
3 0

Answer:

mdmfnndhhdhdnd brnrnhruh hehrbfb hfnfnfbj bdnbdhdh hxhhn ndnnjnxnamkdjjfjfjjdjz hzjsuklshhwhhhèushhhhhdhhhshdùunvcn n nn nn nn n b ncjjnndnhshsb bsbbdnnnns nndnfnkkdgdhp1 gyduia

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Seattle-Pipes Co. produces pipes to be supplied to a Seattle utility company. The requirement of the utility company is that the
Goshia [24]

Answer:

Step-by-step explanation:

Hello!

The study variable is

X: Pipe length.

It is known that this variable has a normal distribution and that the distribution parameter varies depending on the process used to manufacture the pipes.

Process A: μ= 200cm δ= 0.5cm

Process B: μ=201cm δ= 1cm

Process C: μ=202cm δ= 1.5cm

Pipes with a length of 200cm or more will be accepted by the utility company (X≥200), but pipes with less than 200cm length will be rejected (X<200)

a. Using Process C, you need to calculate the probability that the pipe will be rejected, symbolically:

P(X<200)

Using the distribution data of process C you have to standardize the value:

P(Z<(200-202)/1.5)= P(Z<-1.33)= 0.09176

b. The requirements change, accepting any pipe between 199 and 202, you have to calculate the probabilities of the pipes being between those lengths using the three process:

Process A:

P(199≤X≤202) = P(X≤202) - P(X≤199)

P(Z≤(202-200)/0.5)) - P(Z≤(199-200)/0.5))

P(Z≤4) - P(Z≤-2) = 1 - 0.02275 = 0.97725

The probability of the pipe being rejected is 0.02275

Process B:

P(199≤X≤202) = P(X≤202) - P(X≤199)

P(Z≤(202-201)/1)) - P(Z≤(199-201)/1))

P(Z≤1) - P(Z≤-2) = 0.84134 - 0.02275 = 0.81859

The probability of the pipe being rejected is 1-0.81859= 0.18141

Process C:

P(199≤X≤202) = P(X≤202) - P(X≤199)

P(Z≤(202-202)/1.5)) - P(Z≤(199-202)/1.5))

P(Z≤0) - P(Z≤-2) = 0.5 - 0.02275 = 0.47725

The probability of the pipe being rejected is 1-0.47725= 0.52275

The pipes manufactured using process A has fewer chances of being rejected.

c.

Process A costs $140

P(X≥200)= 1 - P(X<200)= 1 - P(Z<0)= 1 - 0.5= 0.5

Process B costs $160

P(X≥200)= 1 - P(X<200)= 1 - P(Z<-1)= 1 - 0.15866= 0.84134

Process C costs $177

P(X≥200)= 1 - P(X<200)= 1 - P(Z<-1.33)= 1 - 0.09176= 0.90824

If they where to make 100 pipes:

Using process A: 100*0.5= 50 pipes will be accepted, so they'll win 50*($200-$140)= $3000

Using process B: 100*0.84134= 84.134≅ 84 pipes will beaccepted, so they'll win 84*($200-$160)= $3360

Using the process C: 100*0.90824= 80.824≅ 90 pipes will be accepted, so they'll win 90*($200-$177)= $2070

As you can see, using process B will maximize the profits.

I hope it helps!

6 0
4 years ago
Write a real world problem that can be represented by the equation 3/4c =21
Rzqust [24]
Hello!!

One possible answer:

"Nathan and Jake make a business deal. Nathan receives three quarters of the money made if he runs Jake's shop for a week. Nathan receives 21 dollars. What was the total amount of money made for that week?"

Hope this helps!! Let me know if you have ANY questions.
3 0
4 years ago
Is it true that x= -5 ? -2(-4x-1)-x+3=−30 Justify your answer.
grandymaker [24]

Answer:

Step-by-step explanation:

here you go mate

step 1

-2(-4x-1)-x+3=−30  equation/Question

step 2

-2(-4x-1)-x+3=−30  distribute

7x+5=-30

step 3

7x+5=-30  subtract 5

7x=-35

step 4

\frac{7x}{7} =\frac{-35}{7}  divide

answer

x=-5

6 0
3 years ago
Read 2 more answers
Write the coordinates of the vertices after a rotation of 180 degrees counterclockwise around the origin.
Umnica [9.8K]

90 degrees you are looking to your side

180 degrees you are looking behind you

around origin of 0,0

the image is flipped into the negative world if it is in posiitve or vice versa

8 0
4 years ago
2/5(g - 7) = 3 <br> can i please get some help..
Flura [38]

Answer:

14.500

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    (2)/(5)*(g-7)-(3)=0

Step by step solution :

STEP

1

:

           2

Simplify   —

           5

Equation at the end of step

1

:

  2              

 (— • (g - 7)) -  3  = 0

  5              

STEP

2

:

Equation at the end of step 2

 2 • (g - 7)    

 ——————————— -  3  = 0

      5        

STEP

3

:

Rewriting the whole as an Equivalent Fraction

3.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  5  as the denominator :

        3     3 • 5

   3 =  —  =  —————

        1       5  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

3.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

2 • (g-7) - (3 • 5)     2g - 29

———————————————————  =  ———————

         5                 5  

Equation at the end of step

3

:

 2g - 29

 ———————  = 0

    5  

STEP

4

:

When a fraction equals zero

4.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 2g-29

 ————— • 5 = 0 • 5

   5  

Now, on the left hand side, the  5  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  2g-29  = 0

Solving a Single Variable Equation:

4.2      Solve  :    2g-29 = 0

Add  29  to both sides of the equation :

                     2g = 29

Divide both sides of the equation by 2:

                    g = 29/2 = 14.500

One solution was found :

g = 29/2 = 14.500

8 0
3 years ago
Read 2 more answers
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