Help me pleaseeeeeeeeeee

The formula to find the period of orbit of a satellite around a planet is T^2=(4pi^2/GM)r^3 where r is the orbit's mean radius,

Natalija [7]

The answer is $r= \sqrt[3]{GMT^{2}/4 \pi^{2}}$

$T^{2} = \frac{4 \pi^{2}}{GM} r^{3}$

Move $\frac{4 \pi^{2} }{GM}$ to the other side of the equation:
$T^{2} /\frac{4 \pi^{2} }{GM} = r^{3} \\ 
T^{2} *\frac{GM}{4 \pi^{2} } = r^{3}$

Rearrange:
$r^{3} = T^{2} *\frac{GM}{4 \pi^{2} } \\ 
r^{3}= \frac{T^{2} *GM}{4 \pi^{2} } \\ 
r^{3}= \frac{GMT^{2}}{4 \pi^{2} } \\ 
r^{3} = GMT^{2}/4 \pi^{2}$

Since $x^{3}= \sqrt[3]{x}$ , then
$r^{3} = GMT^{2}/4 \pi^{2} \\ 
r= \sqrt[3]{GMT^{2}/4 \pi^{2}}$

3 0

3 years ago

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Divide 3m 80cm of ribbon in the ratio of 1/3 : 3/4 : 1/2 what is the result?

JulijaS [17]

Answer:

80 cm / 180 cm / 120 cm

Step-by-step explanation:

the smallest common multiple of 3, 4 and 2 is 12.

so, to be able to truly compare these fractions we need to bring all denominators to .../12.

1/3 = 4/12

3/4 = 9/12

1/2 = 6/12

in total we have therefore 19 (4+9+6) equally large parts of the ribbon that are then combined :

4 parts for the first segment.

9 parts for the second segment

6 parts for the third segment.

so, one part is

380 cm / 19 = 20 cm

therefore the first segment of the ribbon is

4×20 = 80 cm long

the second segment

9×20 = 180 cm long

the third segment

6×20 = 120 cm long

4 0

2 years ago

suppose Mina and two of her friends go to the movies.write an expression that could be used to find the total cost for them to g

Marizza181 [45]

Let x represent the cost of the movie ticket and y represent the cost of a snack item. 3x + 3y

3 0

3 years ago

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MAXIMUM POINT WILL BE GIVEN!!! I NEED THIS RN!!!!!!!!!!!!!!!!!!!!!!!!!

Lemur [1.5K]

Answer:

Part a) The variables are

x (the number of packages of Twinkies that were sold)

y (the number o boxes of juice that were sold)

Part b) The system of equations is

$x+y=79$ and $1.65x+1.36y=118.17$

Part c) $x=37,y=42$

Part d) The value of y represent the number of boxes of juice that were sold $y=42\ boxes\ of\ juice$

The value of x represent the number of packages of Twinkies that were sold $x=37\ packages\ of\ Twinkies$

Step-by-step explanation:

Part a) Define the variables in this situation

Let

x-----> the number of packages of Twinkies that were sold

y----> the number of boxes of juice that were sold

Part b) Write a system of equations that model the problem

we know that

$x+y=79$ ------> equation A

$1.65x+1.36y=118.17$ ---> equation B

Part c) Use the linear combination method to find the solution to the system you wrote in part b

Multiply equation A by -1.65

$-1.65(x+y)=-1.65*79$

$-1.65x-1.65y=-130.35$ ------> equation C

Adds equation C and equation B

$-1.65x-1.65y=-130.35\\1.65x+1.36y=118.17\\---------\\-1.65y+1.36y=-130.35+118.17\\-0.29y=-12.18\\y=42$

Find the value of x

$x+y=79$

$x+42=79$

$x=79-42=37$

Part d) Using a complete sentence, explain what the solution found in part c represents

The value of y represent the number of boxes of juice that were sold

so

$y=42\ boxes\ of\ juice$

The value of x represent the number of packages of Twinkies that were sold

so

$x=37\ packages\ of\ Twinkies$

7 0

3 years ago

Cos(0)=square root 3/3, sin 0<0. what is the value of sin0

abruzzese [7]

Answer:

sin θ = $\frac{\sqrt{6} }{3}$

Step-by-step explanation:

Given that,

cos θ = $\frac{\sqrt{3} }{3}$

From the trigonometric functions,

cos θ = $\frac{adjacent}{hypotenus}$

⇒ adjacent = $\sqrt{3}$ , and the hypotenuse = 3

Let the opposite side be represented by x, applying the Pythagoras theorem we have;

$/hyp/^{2}$ = $/adj/^{2}$ + $/opp/^{2}$

$/3/^{2}$ = $(\sqrt{3} )^{2}$ + $x^{2}$

9 = 3 + $x^{2}$

$x^{2}$ = 9 - 3

= 6

x = $\sqrt{6}$

Thus, opposite side = $\sqrt{6}$

So that,

sin θ = $\frac{opposite}{hypotenuse}$

= $\frac{\sqrt{6} }{3}$

Therefore,

sin θ = $\frac{\sqrt{6} }{3}$

6 0

2 years ago