Answer:
<u>B. Tip the bowl slightly, then spoon up the last bit</u>
Explanation:
Generally speaking none of the other answers made much of sense.. "tip the bowl from side to side" doesn't help you at all, neither does "Keep spooning as much as you can, then stop eating". Neither of these will help you spoon up the last little bit, <u>the most logical answer is B. "Tip the bowl slightly, then spoon up the last bit"</u>. If this is not the correct answer then it'd be D, but I don't believe/feel that it's "poor etiquette" to "leave the last little bit".
Answer:
Explanation:
public static int cupsToOunces (int cups) {
int ounces = cups * 8;
return ounces;
}
This is a very simple Java method that takes in the number of cups in the recipe as a parameter, converts it to ounces, and then returns the number of ounces. It is very simple since 1 cup is equal to 8 ounces, therefore it simply takes the cups and multiplies it by 8 and saves that value in an int variable called ounces.
The tilde operator represents the root directory of the website.
Answer:
Following is the code for filter:
public class filter
{ public static void main(String[] args)
{ int x = StdIn.readInt();
System.out.print(" " + x + " ");
while(!StdIn.isEmpty())
{ int y = StdIn.readInt();
if(y != x)
System.out.print(" " + y + " ");
x = y;
}
}
}
Explanation:
- A public class filter is used.
- The main function will accept a single argument as string[], it is also known as java command line argument.
- Now the Stdln.readInt is used to read the integers in the sequence and store it in integer x.
- The value stored in variable x will be printed using System.out.print
- Now unless the Stdln.readInt gets an empty value, check each value of sequence and store in variable y.
- If y is not equal to previous value x, print it and shift the value of y into x.
- Repeat the loop again.
i hope it will help you!