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ehidna [41]
3 years ago
8

You're allowed to use a cell phone while driving as long as there isn't any oncoming traffic.

Computers and Technology
2 answers:
pochemuha3 years ago
5 0
The answer is false, it is against the law to be on your phone while driving.
Tom [10]3 years ago
4 0

The statement that you're allowed to use a cell phone while driving as long as there isn't any oncoming traffic is false. A cell phone should be never (in none scenario) used while driving. Cell phone distraction is very high. If someone decides to check his or her text messages, emails, phone calls, or any other mobile applications while driving it can lead do serious safety risks.


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Which of the following scanning technique attackers use to bypass firewall rules, logging mechanism, and hide themselves as usua
OLEGan [10]

Answer: Stealth scanning technique

Explanation:

Stealth Scanning technique includes the following steps:

1. The client upon sending a single SYN packet to is responded by SYN/ACK packet if the port is open.

2. The port is assumed to be in closed state if the RST packe t is sent from the server.

3. This RST packet is sent by the client to close the initiation process so that a connection cannot be established.

6 0
3 years ago
Reflection about information technology​
nikitadnepr [17]

Answer:

Reflection on what though?

Explanation:

3 0
3 years ago
What is NOT an issue associated with tag management systems? There is no automation available for tag management systems. Managi
SSSSS [86.1K]

Answer:

Managing tags means experience with the programming language to utilize them.

Explanation:

In different markets, tags are used to assigned prices and values to different products. To make these tags "tag management systems" are deployed to manage and create these tags.

Tag management system is software, that is used to create the tags with ease. There is no need of coding or programming while creating tags.

<em>So we can say that, There is no issue of Managing tags means experience with the programming language to utilize them.</em>

5 0
3 years ago
Write a program that takes in a line of text as input, and outputs that line of text in reverse. The program repeats, ending whe
Nana76 [90]

<u>Answer:</u>

<em>using System; </em>

<em>public class Program </em>

<em>{ </em>

<em> public static void Main() </em>

<em> { </em>

<em> String input ; </em>

<em> while(true) </em>

<em> { </em>

<em>  input = Console.ReadLine(); </em>

<em>  if(input.Equals(""quit"")) </em>

<em>  break; </em>

<em>  Reverse_String(input); </em>

<em> } </em>

<em> return; </em>

<em> } </em>

<em>static void Reverse_String(string input_text) </em>

<em>{ </em>

<em>    char[] text = input_text.ToCharArray(); </em>

<em>    Array.Reverse(text); </em>

<em>    Console.WriteLine(text); </em>

<em>} </em>

<u>Explanation:</u>

<em>In the above program a separate function is written to reverse the string.</em>

This method takes the string as an argument and place it in a array and then use the built-in function reverse and print the reversed string in the console.

<em>In the main(), the input is obtained from the console and it is passed to the reversestring(). </em>

7 0
3 years ago
Read 2 more answers
In this chapter, you saw an example of how to write an algorithm that determines whether a number is even or odd. Write a progra
vagabundo [1.1K]

Answer:

// Program is written in Java Programming Language

// Comments are used for explanatory purpose

// Program starts here

public class RandomOddEve {

/** Main Method */

public static void main(String[] args) {

int[] nums = new int[100]; // Declare an array of 100 integers

// Store the counts of 100 random numbers

for (int i = 1; i <= 100; i++) {

nums[(int)(Math.random() * 10)]++;

}

int odd = 0, even = 0; // declare even and odd variables to 0, respectively

// Both variables will serve a counters

// Check for odd and even numbers

for(int I = 0; I<100; I++)

{

if (nums[I]%2 == 0) {// Even number.

even++;

}

else // Odd number.

{

odd++;

}

}

//.Print Results

System.out.print("Odd number = "+odd);

System.out.print("Even number = "+even);

}

8 0
3 years ago
Read 2 more answers
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