Correct Answer: Option g: <span>adding salt to water lowers its freezing point
Reason:
Freezing point is a colligative property. When a non-volatile solution is present in solution, it's freezing point decreases. This is referred as depression in freezing point (</span>ΔTf<span>). Extent of lowering in freezing point is dependent on number of particles present in system. Mathematically it is expressed as:
</span>ΔTf = Kf X m
<span>
where, m = molality of solution
Kf = cryoscopic constant.
Hence, a</span><span>dding salt to water lowers the freezing point of solution.</span>
<span>Mn's
atomic number is 25 so you have 25 protons and 25 electrons in a
neutral atom. Since no charge is shown, the number of electrons is 25
Ni's atomic number is 28 so you have 28 protons and 28 electrons in a
neutral atom. This one shows a +3 so there are 3 missing electrons, the
number of electrons is 28 - 3 = 25
Cu's atomic number is 29 so you have 29 protons and 29 electrons in a
neutral atom. This one shows a +2 so there are 2 missing electrons, the
number of electrons is 29 - 2 = 27
Ti's atomic number is 22 so you have 22 protons and 22 electrons in a
neutral atom. This one shows a -2 so there are 2 EXTRA electrons, the
number of electrons is 22 + 2 = 24 </span>
A. to push each other away
Answer:
1) the product may be contaminated by the solvent
2) side reactions may yield unwanted products
3) some reactants may be present in the product if the reaction was incomplete
Explanation:
It is common in chemistry to pass reaction products through purification processes. This is done for a number of reasons.
First of all, some solvents molecules may be attached to the reaction product. These solvent particles must be separated in order to obtain a pure product.
Secondly, some side reactions also yield products that are isolated along with the desired products and these must be separated accordingly.
Finally, some chemical reactions do not go on to completion. This implies that some reactants may still be isolated alongside the product at the end of the reaction.
