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horsena [70]
2 years ago
6

Which element is considered a malleable substance? a) sulfur b) radon c) hydrogen d) gold​

Chemistry
2 answers:
IgorLugansk [536]2 years ago
5 0

Answer:

Gold

<em>hope this helps :)</em>

abruzzese [7]2 years ago
4 0

Answer: Gold

Explanation: Gold is called a heavy metal because of its high density, which comes from the fact that each of its atoms is individually very heavy. ... In contrast, gold atoms slide past each other relatively easily, which makes the metal soft and malleable.

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Answer: An acid is defined with having more [H₃O+] ions, and a base is defined with having more [OH-] ions. On the pH scale, an acid has a lower pH and a base has a higher pH. With this being said, the lower the pH, the more [H₃O+] ions are present and the higher the pH, the more [OH-] ions are present.

Explanation:

I hope this helps!! Pls give brainliest!! :)

6 0
1 year ago
Balance the equation and state the limiting reagent in the following reaction:
romanna [79]
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8 0
3 years ago
what is the concentration of a dextrose solution prepared by diluting 14 ml of a 1.0 m dextrose solution to 25 ml using a 25 ml
allsm [11]

The concentration of a dextrose solution prepared by diluting 14 ml of a 1.0 M dextrose solution to 25 ml using a 25 ml volumetric flask is 0.56M.

Concentration is defined as the number of moles of a solute present in the specific volume of a solution.

According to the dilution law, the degree of ionization increases on a dilution and it is inversely proportional to the square root of concentration. The degree of dissociation of an acid is directly proportional to the square root of a volume.

M₁V₁=M₂V₂

Where, M₁=1.0M, V₁=14ml, M₂=?, V₂=25ml

Rearrange the formula for M₂

M₂=(M₁V₁/V₂)

Plug all the values in the formula

M₂=(1.0M×14 ml/25 ml)

M₂=14 M/25

M₂=0.56 M

Therefore, the concentration of a dextrose solution after the dilution is 0.56M.

To know more about dilution

brainly.com/question/18566203

#SPJ4

6 0
10 months ago
Help me its due soon thanks
UkoKoshka [18]

Answer:

B

Explanation:

The gravity accelleration values are the same for both planets.

5 0
3 years ago
Read 2 more answers
The absorbance (????)(A) of a solution is defined as ????=log10(????0????) A=log10⁡(I0I) where ????0I0 is the incident‑light int
bulgar [2K]

Answer:

The absorbance of the myoglobin solution across a 1 cm path is 0.84.

Explanation:

Beer-Lambert's law :

Formula used :

A=\epsilon \times c\times l

A=\log \frac{I_o}{I}

\log \frac{I_o}{I}=\epsilon \times c\times l

where,

A = absorbance of solution

c = concentration of solution

\epsilon = Molar absorption coefficient

l = path length

I_o = incident light

I = transmitted light

Given :

l = 1 cm, c = 1 mg/mL ,\epsilon = 15,000 M^{-1}cm^{-1}

Molar mass of myoglobin = 17.8 kDa = 17.8 kg/mol=17800 g/mol

(1 Da = 1 g/mol)

c = 1 mg /mL = {1mg /mL}{\text{Molar mass of myoglobin}}

c = \frac{1 mg/mL}{ 17800 g/mol} = 5.6179\times 10^{-5} mol/L

1 mg = 0.001 g, 1 mL = 0.001 L

A= 15,000 M^{-1}cm^{-1}\times 5.6179\times 10^{-5} mol/L\times 1 cm

A=0.8426 \approx 0.84

The absorbance of the myoglobin solution across a 1 cm path is 0.84.

5 0
3 years ago
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