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olga2289 [7]
3 years ago
14

Give the name of the element whose neutral atom tends to have 77 electrons.

Chemistry
1 answer:
liraira [26]3 years ago
8 0

Ir, Iridium has 77 electrons when neutral.

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Calculate the standard entropy of vaporization of ethanol at its boiling point, 352 K. The standard molar enthalpy of vaporizati
Korvikt [17]

Answer : The correct option is, (b) +115 J/mol.K

Explanation :

Formula used :

\Delta S=\frac{\Delta H_{vap}}{T_b}

where,

\Delta S = change in entropy

\Delta H_{vap} = change in enthalpy of vaporization = 40.5 kJ/mol

T_b = boiling point temperature = 352 K

Now put all the given values in the above formula, we get:

\Delta S=\frac{\Delta H_{vap}}{T_b}

\Delta S=\frac{40.5kJ/mol}{352K}

\Delta S=115J/mol.K

Therefore, the standard entropy of vaporization of ethanol at its boiling point is +115 J/mol.K

8 0
3 years ago
What was The US Army trying to slove about lake Lenore in 1947
Leviafan [203]

Answer:

1947 the United States Army had an excess of metallic sodium left over from World War II and determined that the alkaline waters of Lake Lenore would be a good spot to dump and neutralize the acidic element, which reacts with water with intense explosions.

Explanation:

there ya go

5 0
3 years ago
How does the troposphere protect the earth?
Usimov [2.4K]
The troposphere protect the molecules because there are higher layers on top. This makes life possible on Earth.
4 0
3 years ago
Chapter 15 Lesson 3 Protecting Earth<br> pointsssssssssssssss
saw5 [17]

Answer:

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Explanation:

4 0
2 years ago
If 2.00 g of N2 occupies 1.25 L space, how many moles of N2
uranmaximum [27]

Answer:

n₂ =1.4 mol

Explanation:

Given data:

Mass of nitrogen = 2 g

Initial Volume occupy by nitrogen = 1.25 L

Final volume occupy by nitrogen = 25.0 L

Final number of moles = ?

Solution;

Formula:

V₁ / n₁ = V₂ / n₂

Number of moles of nitrogen:

Number of moles = mass/ molar mass

Number of moles = 2 g/ 28 g/mol

Number of moles = 0.07 mol

Now we will put the values in formula:

V₁ / n₁ = V₂ / n₂

n₂ = V₂× n₁ /V₁

n₂ = 25 L × 0.07 mol /  1.25 L

n₂ = 1.75 L. mol / 1.25 L

n₂ =1.4 mol

7 0
3 years ago
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