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olga2289 [7]
3 years ago
14

Give the name of the element whose neutral atom tends to have 77 electrons.

Chemistry
1 answer:
liraira [26]3 years ago
8 0

Ir, Iridium has 77 electrons when neutral.

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What is the empirical formula of a compound that is 24.42 % calcium, 17.07 % nitrogen, and 58.5% oxygen?
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Answer:

CaN_{2} O_{6}

Explanation:

When calculating an empirical formula from percentages, assume you have a 100g sample. This allows you to convert the percentages directly to grams, because X % of 100g is X grams.

So:

24.42 % = 24.42 g Ca, 17.07% = 17.07g N, 58.5% = 58.5g O

The next step is to divide each mass by their molar mass to convert your grams to moles.

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Then you will divide all of your mol values by the SMALLEST number of moles. This gives you whole numbers that are the mole ratio (subcripts) of the empircal formula.

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3.680 mol/0.6092 mol = 6

So the empirical formula is CaN_{2} O_{6}

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3 years ago
An atom is described as a nucleus of protons and neutrons surrounded by a(n)
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How do I solve this problem?
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First question. Applying ideal gas equation PV=nRT, P= 101.3 x 10³Pa = 1atm. therefore, 1 x 260 x 10^-3 = n x 0.082 x 294.( Temperature in kelvin=273+21). n = 0.01 moles. Volume of gas at STP= n x 22.4 = 0.01x22.4 = 0.224L. Hope this helps
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