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FromTheMoon [43]
3 years ago
13

Solve independent system equations for: 5x-9y=-6510x-3y=20x=?y=?​

Mathematics
1 answer:
Sergio039 [100]3 years ago
3 0
5x-9y=-65
10x-3y=20

Multiple the first equation by 2
10x-18y=-130
10x -3y=20
Then subtract the two equations to get rid of the x

21y=-150
Divide the -150 by 21
Y=-7.14

Plug the y into the original equation. (Either one)

5x-9(-7.14)=-65
5x-64.28=-65
Then add 64.28 to the -65
5x=-0.72
Divide by 5
X=-0.144

I hope this is right
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2= 2, 4, 6, 8, 10, 12, 14, 16, 18, 20
5=5, 10, 15, 20
  So now, you have to pick out the numbers that are common to both numbers. So;
10, 20
  10 and 20 are the only common numbers. So you have to look for the lowest common number. And that is 10. So the LCM is 10.. Hope i helped. Have a nice day. 
5 0
3 years ago
Sasha is 8 years than ei. the sum of their ages is 14. find the ages os sasha and rei​
snow_lady [41]

Answer:

<h2><u><em>Rei 3 years old</em></u></h2><h2><u><em>Sasha 11 Years old</em></u></h2>

Step-by-step explanation:

sasha is 8 years than ei. the sum of their ages is 14. find the ages os sasha and rei​

(14 - 8) : 2 = 3 (Rei)

8 + 3 = 11 (Sasha)

------------------

11 + 3 = 14

the answer is good

6 0
3 years ago
Andy is scuba diving. he starts at sea level and then descends 10 feet in 212 minutes. part a how would you represent andy's des
Mashcka [7]
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4 0
3 years ago
Suppose a Hispanic Heritage festival is held in an area measuring 2,494 square yards. If the length of the festival is 58 yards,
Kaylis [27]

Answer: 43 yards.

Step-by-step explanation:

Let the shape of the area occupied for festival be rectangle.

and area of rectangle = length x width

Given: Area of the festival= 2,494 square yards.

Length of the festival=  58 yards

Then width = (Area )÷ (length)

=  (2494)÷58  yards

= 43 yards

hence, the  width of the festival = 43 yards.

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