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3 years ago

Which of the following is an advantage of using a debit card compared to using a check or credit card?

Mathematics

1 answer:

ozzi3 years ago

5 0

Answer:

there is no need to focus on keeping your credit score up which can be a good thing and a bad thing

Step-by-step explanation:

You might be interested in

Which of the following shows a group of possible angles a triangle could have?

Delvig [45]

Answer:

C. 60 degrees, 60 degrees, 60 degrees

Step-by-step explanation:

The measures of interior angles of a triangle sum to 180°.

8 0

3 years ago

One gallon of water weighs 8.34 pounds. How much does 6 gallons of water weigh? Show your work, including labeling your answer w

maxonik [38]

Answer:

50.04 pounds

Step-by-step explanation:

If 1 gallon weighs 8.34 pounds,

all you have to do is multiply 8.34 by 6

to get what 6 gallons would weigh.

8 0

3 years ago

A water tank that holds 12,000 gallons

Vitek1552 [10]

Answer:

C. 148

Step-by-step explanation:

Equation: (12,000-8,448)÷24=x

12,000-8448=3552

3552÷24=148

x=148

8 0

3 years ago

How are exponents and radicals used to present roots of real numbers

MissTica

Answer:

$\sqrt[n]{a} =a^{\frac{1}{n}}$

Explanation:

Roots of real numbers can be represented by <em>radicals</em> or by<em> exponents. </em>

First, I present some examples to show how exponents and radicals are related, and then generalize.

$\sqrt{4}=4^{(\frac{1}{2})}=(2^2)^\frac{1}{2}=(2)^{\frac{2}{2}}=2^1=2\\\\\\\sqrt{25}=(25)^{\frac{1}{2}}=(5^2)^{\frac{1}{2}}=(5)^{\frac{2}{2}}=5^1=5$

$\sqrt[3]{8}=(8)^{\frac{1}{3}}=(2^3)^{\frac{1}{3}}=(2)^{\frac{3}{3}}=2^1=2$

When you write 5² = 25, then 5 is the square root of 25.

And in general, if n is a positive integer and $a^n=x$ , then $a$ is the nth root of x.

Also, if n even (and positive) and $a$ is positive, then $a^{\frac{1}{n}}$ is the positive nth root of $a$

Thus,

$\sqrt[n]{a} =a^{\frac{1}{n}}$

5 0

3 years ago

Find the derivative of the function. g(x) = ∫5 x 4 x u2 − 1u2 +1 dug'(x) = g

solniwko [45]

Answer:

$\mathbf{g'(x) = 5 \times \dfrac{(25x^2-1)}{(25x^2+1)}- 4 \times \dfrac{(16x^2-1)}{(16x^2+1)}}$

Step-by-step explanation:

The question can be better structured and represented as :

$g(x) = \int ^{5x}_{4x} \dfrac{u^2-1}{u^2+1} \ du$

now the derivative of the function of g(x) is g'(x) which is equal to:

$g'(x) = \dfrac{(5x)^2-1}{(5x)^2 +1 }\dfrac{d}{dx}(5x) - \dfrac{(4x)^2-1}{(4x)^2 +1 }\dfrac{d}{dx}(4x)$

$\mathbf{g'(x) = 5 \times \dfrac{(25x^2-1)}{(25x^2+1)}- 4 \times \dfrac{(16x^2-1)}{(16x^2+1)}}$

3 0

3 years ago