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Studentka2010 [4]

3 years ago

10

The final cost of an item after

1 answer:

loris [4]3 years ago

7 0

Answer:

31.441696

Step-by-step explanation:

42.86% of 59.36 + 6% = 31.441696

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Does 4x+5y=0 represent a direct variation ?

trapecia [35]

$\bf \qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 4x+5y=0\implies 5y=-4x\implies y=-\cfrac{4}{5}x\qquad \boxed{k=-\cfrac{4}{5}}\qquad \text{\Large\checkmark}$

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4 years ago

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jasenka [17]

Answer: the answer is 19.6

Step-by-step explanation:

just add up by each number, for example 5.6+3 miles is 8.6 miles so just keep adding up the miles to get this answer

3 0

3 years ago

Find all of the zeros of f(x) = 5x^2 +40x-100

Umnica [9.8K]

Answer:the answer is B

Step-by-step explanation:

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4 years ago

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A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the

Basile [38]

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= $\pi r^2h$

According to the problem,

$\pi r^2 h=25$

$\Rightarrow h=\frac{25}{\pi r^2}$

The surface area of the base of the can is = $\pi r^2$

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× $\pi r^2$ )

The lateral surface area of the can is = $2\pi rh$

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× $2\pi rh$ )

$=\$2.5 \pi r h$

Total cost of metal is C= 2.00 $\pi r^2$ + $2.5 \pi r h$

Putting $h=\frac{25}{\pi r^2}$

$\therefore C=2\pi r^2+2.5 \pi r \times \frac{25}{\pi r^2}$

$\Rightarrow C=2\pi r^2+ \frac{62.5}{ r}$

Differentiating with respect to r

$C'=4\pi r- \frac{62.5}{ r^2}$

Again differentiating with respect to r

$C''=4\pi + \frac{125}{ r^3}$

To find the minimize cost, we set C'=0

$4\pi r- \frac{62.5}{ r^2}=0$

$\Rightarrow 4\pi r=\frac{62.5}{ r^2}$

$\Rightarrow r^3=\frac{62.5}{ 4\pi}$

⇒r=1.71

Now,

$\left C''\right|_{x=1.71}=4\pi +\frac{125}{1.71^3}>0$

When r=1.71 cm, the metal cost will be minimum.

Therefore,

$h=\frac{25}{\pi\times 1.71^2}$

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

6 0

3 years ago

A bakery sells 2 croissants for $3 they sold 31 croissants on Monday, how much money did they make

Alisiya [41]

Since 2 croissants = $3 we can work out that 1 croissant = $1.50

Multiply $1.50 by 31 and we get $46.50

Therefore 31 croissants is $46.50

3 0

3 years ago