All categories

3 years ago

Pls help and thank youuuuu

Mathematics

1 answer:

Evgen [1.6K]3 years ago

3 0

Answer:

$y=-2x+4$

Step-by-step explanation:

The gradient = change in y / change in x

When the x value increases by 1, the y value decreases by 2 so -2 / 1 = -2

The y intercept is 4, so it is +4

You might be interested in

A baby elephant has a mass of 100,000 g. How many kilograms does the baby elephant weigh?

slavikrds [6]

100 kg would be the answer...

4 0

4 years ago

Read 2 more answers

Hasil ulangan dari 15 siswa diperoleh data sebagai berikut, 8, 6, 5, 7, 8, 5, 7, 8, 7, 9, 8, 6, 9, 8, 7 , median dari data terse

Inessa05 [86]

The median of this is 8.

6 0

3 years ago

What is the measure of an angle that turns through 3/4 of a complete circle

Elan Coil [88]

270 degrees because a whole circle is 360 degrees so 360×3/4=270

3 0

4 years ago

A survey conducted by the Consumer Reports National Research Center reported, among other things, that women spend an average of

Nookie1986 [14]

Answer:

(a) The probability that a randomly selected woman shop exactly two hours online is 0.217.

(b) The probability that a randomly selected woman shop 4 or more hours online is 0.0338.

Step-by-step explanation:

Let X = time spent per week shopping online.

It is provided that the random variable X follows a Poisson distribution.

The probability function of a Poisson distribution is:

$P (X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0,1,2,...$

The average time spent per week shopping online is, λ = 1.2.

(a)

Compute the probability that a randomly selected woman shop exactly two hours online over a one-week period as follows:

$P (X=2)=\frac{e^{1.2}(1.2)^{2}}{2!} =0.21686\approx0.217$

Thus, the probability that a randomly selected woman shop exactly two hours online is 0.217.

(b)

Compute the probability that a randomly selected woman shop 4 or more hours online over a one-week period as follows:

P (X ≥ 4) = 1 - P (X < 4)

= 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

$=1-\frac{e^{1.2}(1.2)^{0}}{0!}-\frac{e^{1.2}(1.2)^{1}}{1!}-\frac{e^{1.2}(1.2)^{2}}{2!}-\frac{e^{1.2}(1.2)^{2}}{3!}\\=1-0.3012-0.3614-0.2169-0.0867\\=0.0338$

Thus, the probability that a randomly selected woman shop 4 or more hours online is 0.0338.

(c)

Compute the probability that a randomly selected woman shop less than 5 hours online over a one-week period as follows:

P (X < 5) = P (X = 0) + P (X = 1) + P (X = 2) + P (X = 3) + P (X = 4)

$=\frac{e^{1.2}(1.2)^{0}}{0!}+\frac{e^{1.2}(1.2)^{1}}{1!}+\frac{e^{1.2}(1.2)^{2}}{2!}+\frac{e^{1.2}(1.2)^{3}}{3!}+\frac{e^{1.2}(1.2)^{4}}{4!}\\=0.3012+0.3614+0.2169+0.0867+0.0260\\=0.9922$

Thus, the probability that a randomly selected woman shop less than 5 hours online is 0.9922.

8 0

4 years ago

Amy wants to carpet a room that is 12 feet by 8 feet. How many square yards of carpet will she need to complete the room?

Elodia [21]

Firstly, you should find how many square yard is in one square foot.
One square yard= Nine square feet.
then, in order to find the area, you need to multiply 12 by 8, which gives you 96 square feet.
In order to find the square feet, you need to divide 96 by 9 (as 1 square yard is equal to 9 square feet)
When you divide these, you get 10.66
Therefore, Amy needs 10.66 square yards of carpet.
Hope this helps :)

4 0

3 years ago