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Ber [7]
4 years ago
14

For the past several years, the high school theater department has performed a musical in their auditorium. Each year since the

first, they have raised ticket prices by $0.25, however the department has also noticed a decline in the number of people attending each year. This year, they are analyzing the ticket prices, attendance, and sales to determine the ticket price that maximizes their sales. The table shows their ticket sales with respect to the number of times they have increased the price of a ticket.
Mathematics
2 answers:
Alborosie4 years ago
7 0
No picture to show the tabel
Thepotemich [5.8K]4 years ago
6 0

Answer:

i'm pretty sure its D


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A company that teaches self-improvement seminars is holding one of its seminars in Middletown. The company pays a flat fee of $1
Nutka1998 [239]

Answers:

To reach the breakeven point, how many attendees will that take?  <u>   117   </u>

What will be the company's total expenses and revenues?  <u>    $1755  for each   </u>

=============================================================

Explanation:

x = number of attendees

C(x) = cost function for the company

C(x) = 14x+117

This is because the company pays $14 per person, so x of them accounts for 14x dollars. Then we add on the flat fee of $117 to get 14x+117 dollars overall.

In contrast, the revenue is

R(x) = 15x

because each attendee brings in $15 for the company

The breakeven point is when the cost and revenue are the same. This produces a profit of $0.

R(x) = C(x)

15x = 14x+117

15x-14x = 117

x = 117

If 117 people attend the seminar, then the company breaks even.

To check this, we'll compute the cost and revenue

C(x) = 14x+117

C(117) = 14*117+117

C(117) = 1755

R(x) = 15x

R(117) = 15*117

R(117) =  1755

The cost and revenue is $1755 for each. Because we get the same value, this confirms the correct x value.

Since 117 people is the breakeven point, the company should aim for an attendee count above this, so they can get a positive profit. At some point, there is a max capacity so x can't go up forever.

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its X < 1 or x > 3

where every the point goes is where the graph goes is what I do

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