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Scorpion4ik [409]
2 years ago
5

A field is a rectangle with a perimeter of 960 feet. The length is 100 feet more than the width. Find the width and length of th

e rectangular field.
Mathematics
1 answer:
marta [7]2 years ago
4 0
To start, let x represent the width and x+100 represent the length.

Since the perimeter of a figure is the sum of all the measurements of the side which can be represented by (x+100)+(x+100)+x+x and since you know your perimeter is 960 feet, you can set the expression equal to 960. This would look like this:
(x+100)+(x+100)+x+x=960

Once you have done that, combine any like terms (combine terms with the same variables and raised to the same power together) which would simplify to this:
4x+200=960

Now that you have your like terms simplified, subtract 200 from both sides to get 4x=760 and finally, to solve for x, or find the width, divide both sides by 4 to get x=190.

Now that you have your width, now you must find your length as the question asks to find the dimensions of the rectangular field. To find the length, add 100 to the width of (190) since according to the information given, the length is 100 more than the width. When you add 100 to 190, you should get that your length is 290.

Now that you have your length and width, you can conclude that the dimensions of the field is 190 by 290 feet, which is your answer :)
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Answer:

The equation of line in the form of Ax + By = C is: \mathbf{4x+y=-17}

Step-by-step explanation:

We need to find the equation of line, having slope m = -4 and passes through point (-2,-9)

First we need to find slope and y-intercept of the line.

The slope is given i.e. m = -4

Now, we need to find the y-intercept

Using the point (-2,-9) and slope m = -4, y-intercept can be found using:

y=mx+b\\-9=-4(-2)+b\\-9=8+b\\b=-9-8\\b=-17

Now, the equation of required line having slope m = -4 and y-intercept b = -17 is:

y=mx+b\\y=-4x-17

Now writing in form of Ax + By = C

y=-4x-17\\4x+y=-17

So, the equation of line in the form of Ax + By = C is: \mathbf{4x+y=-17}.

5 0
3 years ago
Which values are solutions to the inequality below? √x ≤ 5
Romashka [77]
\sqrt{x}  \leq 5

Find the real  region  for \sqrt{x}

\sqrt{x} is real for x \geq 0

= x  \geq 0

\sqrt{x}  \leq 5

Square both sides:

( \sqrt{x} )^2  \leq 5^2

5^2 = 5*5 =25

Refine:

x  \leq 25

Answer D

hope this helps!


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3 years ago
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almond37 [142]
It is a beacuse it’s is q that’s all
8 0
3 years ago
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TEA [102]
What do you need to know
6 0
3 years ago
I need help with this i really dont understand it. :)
nikdorinn [45]

Answer:

see explanation

Step-by-step explanation:

Given 2 sides of a triangle then the third side x is in the range

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(11)

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6 0
3 years ago
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