What is the equation of (0,2) and (3,0)
1 answer:
Let's first find the slope. This is (y_2 - y_1)/(x_2 - x_1), where (x_1, y_1) and (x_2, y_2) are points.
For this problem, our slope is (0 - 2)/(3 - 0) = -2/3.
We can now use the point-slope formula to find the equation of our line:
(y - y_1) = m(x - x_1)
(y - 2) = -2/3(x - 0)
y - 2 = (-2/3)x
y = (-2/3)x + 2
The equation of our line is
.
For this problem, our slope is (0 - 2)/(3 - 0) = -2/3.
We can now use the point-slope formula to find the equation of our line:
(y - y_1) = m(x - x_1)
(y - 2) = -2/3(x - 0)
y - 2 = (-2/3)x
y = (-2/3)x + 2
The equation of our line is
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Answer:
His book was opened at Page no.296 and Page no.297
Step-by-step explanation:
Let the page number of one page be x
Page number of page facing page no. x = x+1
We are given that the product of the facing pages was 87,912.
So, x(x+1)=87912
(x+297)(x-296)=0
x=296,-297
Since Page no. cannot be negative
So, x=296
x+1=296+1=297
So, his book was opened at Page no.296 and Page no.297